4

例如，假设我有一个键处理接口，在 C++ 中定义为：

class KeyBoardHandler 
{ 
public:
    virtual onKeyPressed(const KeyEventArgs& e);
    virtual onKeyReleased(const KeyEventArgs& e);
}

现在，我想将其扩展到 Lua，以允许 Lua 利用并在脚本中注册一个 KeyboardHandler。

这是到目前为止的原型。

class ScriptKeyboardHandler : public KeyboardHandler
{
public:
    ... previous methods omitted
    static void createFromScript(lua_State* L);
    bool createCppData();

private:
    ScriptKeyBoardHandler(lua_State* L);

    int mSelf;
    int mKeyPressFunc;
    int mKeyReleaseFunc;
    lua_State* mpLuaState;
}

现在，我知道实现将是这样的：

ScriptKeyboardHandler::ScriptKeyboardHandler(lua_State* L) :
    mpState(L)
{ }

ScriptKeyboardHandler::onKeyPressed(...) { 
     // check if mKeyPressFunc is a function
     // call it, passing in mself, and the event args as params
} 

// On Key Release omitted because being similar to the key pressed

ScriptKeyboardHandler::createFromScript(lua_State* L)
{
    auto scriptKeyboardHandler = new ScriptKeyboardHandler(L);
    if (scriptKeyboardHandler->createCppData())
    {
        // set the light user data and return a reference to ourself (mSelf)
    }
}

ScriptKeyboardHandler::createCppData() 
{
    // get the constructor data (second param) and find the keyPressed and keyReleased function, store those for later usage
    // any other data within the constructor data will apply to object
}

-- Syntax of the lua code
MyScriptHandler = { }
MyScriptHandler.__index = MyScriptHandler

MyScriptHandler.onKeyPress = function(self, args)
end

handler = createScriptHandler(handler, MyScriptHandler)
registerKeyHandler(handler)

当函数作为参数传入表中时，我只是不知道如何找到它们。

我这样做对吗？我希望我是，这很痛苦，因为 tolua 不容易支持虚拟类，而不是那些你可以在脚本中派生的类。

我不担心其他功能，只是如何从我的 C 代码中找到这些变量（按键功能等）

4

1 回答 1

2

这大概是我的实现的onKeyPressed样子。

void ScriptKeyboardHandler::onKeyPressed()
{
   //Get the table corresponding to this object from the C registry
   lua_pushlightuserdata(mpLuaState, this);
   lua_gettable(mpLuaState,LUA_REGISTRYINDEX);

   //Now get the function to call from the object
   lua_pushstring(mpLuaState,"onKeyPress");
   lua_gettable(mpLuaState,-2);

   //Now call the function 
   lua_pushvalue(mpLuaState, -2 ); // Duplicate the self table as first argument
   //TODO: Add the other arguments
   lua_pcall(mpLuaState, 1, 0, 0 ); // TODO: You'll need some error checking here and change the 1 to represent the number of args.

   lua_pop(mpLuaState,1); //Clean up the stack

}

但是，您还需要更新构造函数以将表示处理程序的 lua 对象存储到注册表中。

于 2012-08-19T03:36:59.263 回答