c# - 在 wpf 中为 DrawImage 使用 sql 数据库图像

Question

关于这个片段：

dc.DrawImage(new BitmapImage(new Uri(@"E:\Images\Pic1.png", UriKind.Relative)), new System.Windows.Rect(140, 170, 150, 150));

如果我们使用 sql 数据库中的图像进行绘图，我们该怎么做呢？

谢谢

Answer 1

http://www.codeproject.com/Articles/10861/Storing-and-Retrieving-Images-from-SQL-Server-usin

1. 创建sql表

   CREATE TABLE [dbo].[tblImgData]
   (
       [ID] [int] NOT NULL ,
       [Name] [varchar] (50) COLLATE SQL_Latin1_General_CP1_CI_AS NULL ,
       [Picture] [image] NULL
   ) ON [PRIMARY] TEXTIMAGE_ON [PRIMARY]
   

2. 从本地计算机获取图像

    protected void LoadImage()
       {
           try
           {
               this.openFileDialog1.ShowDialog(this);
               string strFn=this.openFileDialog1.FileName;
               this.pictureBox1.Image=Image.FromFile(strFn);
               FileInfo fiImage=new FileInfo(strFn);
               this.m_lImageFileLength=fiImage.Length;
               FileStream fs=new FileStream(strFn,FileMode.Open, 
                                 FileAccess.Read,FileShare.Read);
               m_barrImg=new byte[Convert.ToInt32(this.m_lImageFileLength)];
               int iBytesRead = fs.Read(m_barrImg,0, 
                                Convert.ToInt32(this.m_lImageFileLength));
               fs.Close();
           }
           catch(Exception ex)
           {
               MessageBox.Show(ex.Message);
           }
       }
   

3. 将图像保存在数据库中

   private void btnSave_Click(object sender, System.EventArgs e)
   {
       try
       {
           this.sqlConnection1.Open();
           if (sqlCommand1.Parameters.Count ==0 )
           {
               this.sqlCommand1.CommandText="INSERT INTO tblImgData(ID," + 
                              " Name,Picture) values(@ID,@Name,@Picture)";
               this.sqlCommand1.Parameters.Add("@ID", 
                                System.Data.SqlDbType.Int,4);
               this.sqlCommand1.Parameters.Add("@Name", 
                                System.Data.SqlDbType.VarChar,50);
               this.sqlCommand1.Parameters.Add("@Picture", 
                                System.Data.SqlDbType.Image);
           }
   
           this.sqlCommand1.Parameters["@ID"].Value=this.editID.Text;
           this.sqlCommand1.Parameters["@Name"].Value=this.editName.Text;
           this.sqlCommand1.Parameters["@Picture"].Value=this.m_barrImg;
   
           int iresult=this.sqlCommand1.ExecuteNonQuery();
           MessageBox.Show(Convert.ToString(iresult));
       }
       catch(Exception ex)
       {
           MessageBox.Show(ex.Message);
       }
       finally
       {
           this.sqlConnection1.Close();
       }
   }