我在 Doctrine2 中找不到任何有关命名查询的文档。请帮忙。Doctrine2 有命名查询功能吗?
4 回答
您可以使用
命名查询 - DQL。例子
use Doctrine\ORM\Mapping\NamedQuery; use Doctrine\ORM\Mapping\NamedQueries; /** * @Entity * @Table(name="cms_users") * @NamedQueries({ * @NamedQuery(name="activated", query="SELECT u FROM __CLASS__ u WHERE u.status = 1") * }) */ class CmsUser {}
并称它为
$this->getDoctrine()->getRepository('MyBundle:CmsUser') ->createNamedQuery('activated') ->getResult();
NamedNativeQuery - SQL。更多信息在这里:http ://docs.doctrine-project.org/en/latest/reference/native-sql.html#named-native-query
在 EntityRepository 中收集查询,例如:
namespace Acme\StoreBundle\Repository; use Doctrine\ORM\EntityRepository; class ProductRepository extends EntityRepository { public function findAllOrderedByName() { return $this->getEntityManager() ->createQuery('SELECT p FROM AcmeStoreBundle:Product p ORDER BY p.name ASC') ->getResult(); } }
更多信息:http: //symfony.com/doc/current/book/doctrine.html#custom-repository-classes
类似主题: https://groups.google.com/forum/?fromgroups#!topic/doctrine-user/K-D5ta5tZ3Y[1-25]
也许您会对 EntityRepositories 感兴趣,您可以在其中创建和存储复杂的 Doctrine 查询,并在您想要的项目中调用主题:
http://symfony.com/doc/current/book/doctrine.html#custom-repository-classes
如果您不想弄乱实体定义,则可以在存储库的构造函数中调用注释符号内部使用的函数:
namespace MyBundle\Repository;
use Doctrine\ORM\EntityRepository;
class CmsUserRepository extends EntityRepository
{
public function __construct($em, \Doctrine\ORM\Mapping\ClassMetadata $class)
{
$this->getClassMetadata()->addNamedQuery(array(
'name' => 'activated',
'query' => 'SELECT u FROM __CLASS__ u WHERE u.status = 1'
));
}
}
您还可以__CLASS__
将语句的一部分替换为实体的名称空间和类,例如MyBundle\Entity\CmsUser
我发现这个问题正在寻找本地命名查询示例,上面的答案对我有帮助,所以我想我会分享如何以同样的方式进行本地命名查询。
将此添加到您的实体存储库的构造函数中
public function __construct($em, \Doctrine\ORM\Mapping\ClassMetadata $class)
{
parent::__construct($em, $class);
$this->getClassMetadata()->addNamedNativeQuery(
array('name' => 'published',
'query' => 'SELECT
t0.id AS id,
t0.tracking_uri AS tracking_uri,
t0.name AS name,
t0.description AS description,
t0.url_name AS url_name,
t0.status_type_id as status_type_id
FROM
store.store t0
WHERE
t0.status_type_id = 2',
'resultClass' => '__CLASS__',
'resultSetMapping' => array('entities' => array('entityClass' => '__CLASS__',
'fields' => array('id' => 'id',
'tracking_url' => 'tracking_url',
'name' => 'name',
'description' => 'description',
'url_name' => 'url_name',
'status_type' => 'status_type_id')))));
}
这是我的测试片段
public function testNamedNativeQueryPublished()
{
$results = $this->em->getRepository('MyBundle:Store')->createNativeNamedQuery('published')->execute();
foreach ($results as $store)
{
$this->assertEquals(2, $store->getStatusType());
}
}