9

使用常规控制器,我可以通过返回 FileResult 来做到这一点。这似乎不适用于 ApiController。可以做到吗?这甚至是正确的做法吗?

4

2 回答 2

6

尝试这个。

[HttpGet]    
public HttpResponseMessage Get()
    {
        var file = HttpContext.Current.Server.MapPath("~/Images/accent.png");
        var stream = new FileStream(file, FileMode.Open);
        var content = new HttpResponseMessage(HttpStatusCode.OK)
                         {
                             Content = new StreamContent(stream)
                         };
        content.Content.Headers.ContentType = new MediaTypeHeaderValue("application/octet-stream");
        return content;
    }
于 2012-08-18T19:34:24.580 回答
4

由于这个问题,我有这个工作。

using System.Net;
using System.Net.Http;
using System.Net.Http.Headers;
using System.Web.Http;

namespace Web.Controllers
{
    //usage: /download/report

    [RoutePrefix("download")]
    public class DownloadController : ApiController
    {
        [HttpGet("report")]
        public HttpResponseMessage Report()
        {
            using (var service = new Client())
            {
                var report = service.BuildReport();

                return DownloadResponse(report, "Report.csv");
            }
        }

        private static HttpResponseMessage DownloadResponse(string content, string fileName)
        {
            var downloadContent = new StringContent(content);

            var mediaType = new MediaTypeHeaderValue("application/octet-stream");
            var disposition= new ContentDispositionHeaderValue("attachment") { FileName = fileName };

            downloadContent.Headers.ContentType = mediaType;
            downloadContent.Headers.ContentDisposition = disposition;

            var result = new HttpResponseMessage(HttpStatusCode.OK)
            {
                Content = downloadContent
            };

            return result;
        }
    }
}
于 2014-09-25T13:20:24.837 回答