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我在这里的第一篇文章，即使我是这个非常有用的网站的常客

我想知道是否有人可以帮助我解决以下问题：

我正在用 MySQL 为我的公司编写一个简单的库存检查解决方案，我仍然是新手，但正在学习。

我们有以下搜索表单，当输入产品的条形码时显示来自数据库的结果，我要做的是在结果底部有一个按钮，上面写着“检查确定”，它将信息重新提交给数据库，更新时间戳，并有一个隐藏字段将“状态”更改为已检查。

数据库名称为“stock” 表名称为“main_stock” 字段为：id curr_timestamp mastercategory category product_desc 条码序列状态

每次搜索只给出一个结果，因为条形码是唯一的

我坚持的一点是如何将结果转换为表格以便能够将它们重新提交回数据库

这仅供受保护网络内部使用，非常感谢任何帮助

谢谢

乔恩

    <?php



    $dbHost = 'localhost'; // localhost will be used in most cases

    // set these to your mysql database username and password.

    $dbUser = 'xxxxxxxx'; 
    $dbPass = 'xxxxxxx';
    $dbDatabase = 'stock'; // the database you put the table into.

    $con = mysql_connect($dbHost, $dbUser, $dbPass) or trigger_error("Failed to connect to MySQL         Server. Error: " . mysql_error());
    mysql_select_db($dbDatabase) or trigger_error("Failed to connect to database {$dbDatabase}.         Error: " . mysql_error());

    // Set up our error check and result check array

    $error = array();
    $results = array();

    // First check if a form was submitted. 
    // Since this is a search we will use $_GET

    if (isset($_GET['search'])) {   
    $searchTerms = trim($_GET['search']);   
    $searchTerms = strip_tags($searchTerms); // remove any html/javascript.      

    if (strlen($searchTerms) < 2) {      
    $error[] = "Search terms must be longer than 2 characters.";   
    }else {      
    $searchTermDB = mysql_real_escape_string($searchTerms); // prevent sql injection.   
    }      

    // If there are no errors, lets get the search going.   

    if (count($error) < 1) {      
    $searchSQL = "SELECT mastercategory, category, product_desc, barcode, serial FROM main_stock         WHERE ";            

    // grab the search types.      
    $types = array();      
    $types[] = isset($_GET['barcode'])?"`barcode` LIKE '%{$searchTermDB}%'":''; 
    $types = array_filter($types, "removeEmpty"); // removes any item that was empty (not         checked)            

    if (count($types) < 1)         
    $types[] = "`barcode` LIKE '%{$searchTermDB}%'"; // use the body as a default search if none are checked                

    $andOr = isset($_GET['matchall'])?'AND':'OR';      
    $searchSQL .= implode(" {$andOr} ", $types) . " ORDER BY `barcode`"; // order by title.      
    $searchResult = mysql_query($searchSQL) or trigger_error("There was an error.<br/>" .         mysql_error() . "<br />SQL Was: {$searchSQL}");            

    if (mysql_num_rows($searchResult) < 1) {         
    $error[] = "The scanned barcode {$searchTerms} is not in the database.";      
    }else {         
    $results = array(); // the result array         
    $i = 1;         
    while ($row = mysql_fetch_assoc($searchResult)) {            
    $results[] = "{$i}:Product Name&nbsp;:&nbsp;<br />&nbsp;&nbsp;{$row['product_desc']}        <br />Master Category&nbsp;:&nbsp;<br />&nbsp;&nbsp;{$row['mastercategory']}<br />Sub         Category&nbsp;:&nbsp;<br />&nbsp;&nbsp;{$row['category']}<br />Barcode&nbsp;:&nbsp;{$row['barcode']}        <br />Serial No.&nbsp;:&nbsp;{$row['serial']}";            
    $i++;         
    }      
    }   
    }
    }
    function removeEmpty($var) {   
    return (!empty($var)); 
    }?>

    <html>   

    <title>Search Form</title>   
    <BODY onLoad="document.forms.searchForm.search.focus()">  
    <form action="index.php">
  <center>
    <span class="formcentjc">
      <input type=submit value="Home" />
      </span>
  </center>
</form>  
    <?php echo (count($error) > 0)?"The following had errors:<br /><span id=\"error\">" . implode("<br />", $error) . "</span><br /><br />":""; ?>      

    <form action="<?php echo $_SERVER['PHP_SELF'];?>" method="GET" name="searchForm" class="cent">
    <onLoad="document.searchForm.search()">
    <table width="196" border="1">
     <tr>
        <th bgcolor="#D6D6D6" style="text-align: center" scope="col">Search For:</th>
      </tr>
      <tr style="text-align: center">
        <td class="cent1">
          <input name="search" type="text" onFocus="this.value='';" value="<?php echo isset        ($searchTerms)?htmlspecialchars($searchTerms):''; ?>" size="28" maxlength="15" />
          <span style="text-align: center"></span></td>
      </tr>
    </table>
    </form> 
    <p>
     <tr>
        <td bgcolor="#D6D6D6"><form action="addproduct.php">
          <center>
             <span class="formcentjc">
              <input type=submit value="Add New Product" />
              </span>
          </center>
        </form></td>
      </tr>
      <tr>
    </p>

    <?php 
    echo (count($results) > 0)?"SUCCESS: {$searchTerms} :<br /><br />" . implode("", $results):""; 
    ?>   
    </body>
    </html>
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1 回答 1

0

欢迎来到 StackOverflow！

这里的想法是从数据库中获取数据，然后重新填充表单。当我这样建页面的时候，我通常在URL中有一个参数包含MySQL行的主键，我要抓取，像这样mypage.php?id=37。

如果$_GET['id']设置并且是数字，那么我运行这样的查询：

$id = mysqli::real_escape_string($_GET['id']);
$data = mysqli::query("SELECT * FROM table WHERE id = '{$id}'");

//Check to see if we got any data back :)

然后，我们可以再次填充表单：

<input name="value1" type="hidden" value="<?php echo stripslashes($data['value1'])" />

再次从用户提交数据后，运行如下查询：

$id = mysqli::real_escape_string($_GET['id']);
$value1 = mysqli::real_escape_string($_POST['value1']);
$value2 = mysqli::real_escape_string($_POST['value2']);
mysqli::query("UPDATE table SET value1='{$value1}', value2='{$value2}' ... WHERE id = '{$id}' LIMIT 1");

编辑：

根据我收集的信息，您在详细信息页面上的按钮将提交（我猜是产品名称）其中一个返回的产品返回到数据库，以及搜索它的时间和某种状态。

当您遍历获取的结果数组以将它们显示给用户时，我会收集产品的名称并将其推送到这样的数组中：

$fetchedProducts = array();

while (/*Loop condition to loop through fetched results*/) {
  array_push($loopVariable['productName'], $fetchedProducts);

  //Build HTML to display results
}

//Insert into database
$products = mysqli::real_escape_string(json_encode($fetchedProducts));
$timestamp = strtotime("now");
$status = "some status";

mysqli::query("INSERT INTO searchRecords (
                  `id`, `products`, `timestamp`, `status`
               ) VALUES (
                  NULL, '{$products}', '{$timestamp}', '{$status}'
               )");

希望有帮助。

于 2012-08-17T16:14:44.203 回答