我需要将变量中包含的文本字符串转换为 XML 节点。到输出 XML 的映射由名为“mapping.xml”的文件确定。它具有位操作(检查位是否为 1)。
mapping.xml
<Root>
<field no="2" charlength="2">variable</field>
<field no="3" total="4">fixed</field>
<field no="21" charlength="2">
<subfield no="1" total="3">fixed</subfield>
<subfield no="2" charlength="2" idcode="ABC">variable</subfield>
</field>
<field no="63" charlength="2">
<format1>
<subfield no="1" total="3">fixed</subfield>
</format1>
<format2>
<subfield no="1" total="3">fixed</subfield>
<subfield no="2" total="7">fixed</subfield>
</format2>
<format3>
<subfield no="1" total="3">fixed</subfield>
<subfield no="2" total="7">fixed</subfield>
<subfield no="3" total="6">fixed</subfield>
</format3>
</field>
</Root>
1) The xml will have 64 'field' elements. For a sample, i have included 3 to four fields here, in the mapping xml
2) Always the string will follow the order, fields 1 to 64 in ascending.
3) The fields can be fixed or variable. Fixed means the string will be of number of characters, determined by the charlength attribute corresponding to a field
4) Some fields can have subfields
5) The subfields can have fixed and variable. All fixed ones occur first, followed by the variable subfields.
6) A field which has subfields, fixed ones(subfields) always occur, fixed one does not have idcode attributes.
7) A Field which has subfields, variable ones(subfields), start with 'idcode' attribute, followed by the charlength(determined by the charlength attribute)
8) The subfield idcodes and lengths always occur, however the data may or may not be present, depending on char length(if characters determined by charlength is 0, then the data will not be there)
9) Field no 63 is an exception, where the character length determines the format of the field. If the character is 03(number of chars 2), it is format1. If it is 10, format2, then if it is 16, format3.
9) The occurence of fields, determined by bit positions(0 means no occurence, 1 stands for occurence)
10)The bit positions is determined by another variable which holds a hex value(8 bytes - 64 bits)
我的十六进制可能是:
<xsl:variable name="hex" select="'6000080000000000'"/><!--16 digits, each digit represents fourbits-->
as illustrated below
0110 0000 0000 0000 0000 1000 0000 0000 0000 0000 0000 0000 0000 0000 0000 0000
6 0 0 0 0 8 0 0 0 0 0 0 0 0 0 0
这个十六进制表示存在字段 2、3 和 21,作为这些位置,我们有 1(set)
如果字符串变量是(我的输入)
<xsl:variable name="inputstring" select="'013112316145ABC0812345678'"/>
上面的字符串 16(在 1123 之后),代表字段 21 的字符长度。
我想要的输出:
<Root>
<field2>3</field2>
<!--value is 3 as the charlength is 2(which is 01)-->
<field3>1123</field3>
<!--field3 value is 1123 as it is fixed, total length of 4-->
<field21>
<subfield1>145</subfield1>
<!--subfield1 should be 145 as it is fixed length of total 3 chars-->
<subfield2>12345678</subfield2>
<!--subfield2 starts with 'ABC', has length 08 chars-->
</field21>
</Root>
最后,我们如何将 XML 节点转换回十六进制字符串?