6

假设我有一个包含许多行的表，如下所示：

ID        Range         Range_begining        Profit
----------------------------------------------------
 1    (100-150)                    100           -20
 2    (200-250)                    200          40.2
 3    (100-150)                    100           100
 4    (450-500)                    450           -90
 ...

我正在做一个这样的简单查询：

SELECT max([Range]) AS 'Range'
     , count(ID) AS 'Count'
     , round(avg([Profit]), 2) AS 'AVG Profit'
    FROM
        Orders
    GROUP BY
        Range_begining

运行此查询后，我得到如下结果：

Range        Count        AVG Profit
------------------------------------
(100-150)        2                40
(200-250)        1              40.2
(450-500)        1               -90
 ...

非常简单 ：）

我现在需要做的是选择计数大于 10 的具有最小和最大利润的行（这是一个参数）

我能够通过这个获得最小值：

SELECT TOP 1 [Range], [AVG Profit] FROM (
     SELECT max([Range]) AS 'Range'
         , count(ID) AS 'Count'
         , round(avg([Profit]), 2) AS 'AVG Profit'
        FROM
            Orders
        GROUP BY
            Range_begining) X
WHERE
    [Count]>10
ORDER BY 
    [AVG Profit] ASC --or DESC if I want max profit

我正在考虑UNION使用 ORDER BY DESC 进行上述查询，但这不是最好的解决方案。

我需要做的：
选择 2 行：按 Range 分组时，第一行是最小值，第二行是 AVG 利润最大值。

编辑： 如果我将 2 个移动列添加到我的主数据表中，如下所示：

ID        Range         Range_begining        Profit        OrderDate     Company
---------------------------------------------------------------------------------
 1    (100-150)                    100           -20        2012-01-02          1
 2    (200-250)                    200          40.2        2012-03-22          0
 3    (100-150)                    100           100        2012-02-05          0
 4    (450-500)                    450           -90        2012-05-12          1
 ...

然后尝试添加另外 2 个这样的条件：

; with ordering as (
  SELECT max([Range]) AS 'Range'
     , count(ID) AS 'Count'
     , round(avg([Profit]), 2) AS 'AVG Profit'
     , row_number() over (order by avg([Profit])) rn_min
     , row_number() over (order by avg([Profit]) desc) rn_max
    FROM
        Orders
    GROUP BY
        Range_begining
    HAVING COUNT(ID) > 10
    AND [Company]=@company
    AND (@from= '' OR [OrderDate]>=@from)
    AND (@to= '' OR [OrderDate]<=@to)
)
select [range], [count], [avg profit]
  from ordering
 where (rn_max = 1 or rn_min = 1)

我收到一个错误，因为 [Company] 和 [OrderDate]

在 HAVING 子句中无效，因为它不包含在聚合函数或 GROUP BY 子句中。

我怎样才能解决这个问题？

EDIT2 得到它的工作！

; with ordering as (
  SELECT max([Range]) AS 'Range'
     , count(ID) AS 'Count'
     , round(avg([Profit]), 2) AS 'AVG Profit'
     , row_number() over (order by avg([Profit])) rn_min
     , row_number() over (order by avg([Profit]) desc) rn_max
    FROM
        Orders
    WHERE
    [Company]=@company
    AND (@from= '' OR [OrderDate]>=@from)
    AND (@to= '' OR [OrderDate]<=@to)
    GROUP BY
        Range_begining
    HAVING COUNT(ID) > 10
)
select [range], [count], [avg profit]
  from ordering
 where (rn_max = 1 or rn_min = 1)

编辑 3 我可以返回另一列，其描述如下：

Range        AVG Profit               Description
-------------------------------------------------
(200-250)          40.2           Max profit here
(450-500)           -90     Min profit, well done

编辑 4 快速回答（基于@Nikola Markovinović 回答）：

; with ordering as (
  SELECT max([Range]) AS 'Range'
     , count(ID) AS 'Count'
     , round(avg([Profit]), 2) AS 'AVG Profit'
     , row_number() over (order by avg([Profit])) rn_min
     , row_number() over (order by avg([Profit]) desc) rn_max
    FROM
        Orders
    WHERE
    [Company]=@company
    AND (@from= '' OR [OrderDate]>=@from)
    AND (@to= '' OR [OrderDate]<=@to)
    GROUP BY
        Range_begining
    HAVING COUNT(ID) > 10
)
    SELECT
    CASE WHEN rn_max=1 THEN 'This is max' ELSE 'Min' END AS 'Description'
    ,[range]
    ,[count]
    ,[avg profit]
    FROM ordering
    WHERE (rn_max = 1 or rn_min = 1)
4

2 回答 2

7

您可以使用窗口函数立即执行此操作：

; with ordering as (
  SELECT max([Range]) AS 'Range'
     , count(ID) AS 'Count'
     , round(avg([Profit]), 2) AS 'AVG Profit'
     , row_number() over (order by avg([Profit])) rn_min
     , row_number() over (order by avg([Profit]) desc) rn_max
    FROM
        Orders
    GROUP BY
        Range_begining
    HAVING COUNT(ID) > 10
)
select [range], [count], [avg profit],
       case when rn_max = 1 
            then 'Max profit'
            else 'Min profit'
        end Description
  from ordering
 where (rn_max = 1 or rn_min = 1)

这是 Sql Fiddle 示例。

于 2012-08-17T08:14:17.973 回答
2

这是一个SQLFiddle 示例。在您的最后一个问题查询中，您可以使用 HAVING 而不是嵌套查询：

select * from
(SELECT TOP 1
    max([Range]) AS 'Range'
     , count(ID) AS 'Count'
     , round(avg([Profit]), 2) AS 'AVG Profit'
    FROM
        Orders
    GROUP BY
        Range_begining
    having count(id)>10
    order by round(avg([Profit]), 2) ASC
) a
union all
select * from 
(
SELECT TOP 1
    max([Range]) AS 'Range'
     , count(ID) AS 'Count'
     , round(avg([Profit]), 2) AS 'AVG Profit'
    FROM
        Orders
    GROUP BY
        Range_begining
    having count(id)>10
    order by round(avg([Profit]), 2) desc
)b
于 2012-08-17T08:02:25.310 回答