ruby - 如何使用 Ruby 数组的元素作为哈希键？

Question

所以让我改一下这个问题：

我有两个要比较的哈希值。在我的代码中的某个时刻，我得到了一个响应，例如..

@moves = {:wm01 => {:a1=>"O", :a2=>" ", :a3=>" ", :b1=>" ", :b2=>"O", :b3=>" ", :c1=>" ", :c2=>" ", :c3=>" "}

这对应于一个答案键哈希...

@anskey={
    :wm01=>":c3",:wm02=>":c2",:wm03=>":c1",:wm04=>":b3",:wm05=>":b1",:wm06=>":a3",:wm07=>":a2",:wm08=>":a1",
    :wm09=>":a3",:wm10=>":c1",:wm11=>":a1",:wm12=>":c3",:wm13=>":c3",:wm14=>":c1",:wm15=>":c3",:wm16=>":a1",
    :wm17=>":b1",:wm18=>":b2",:wm19=>":b3",:wm20=>":a2",:wm21=>":b2",:wm22=>":b2",:wm23=>":c2",:wm24=>":b2"
  }

在这种情况下，我需要迭代 @anskey where @moves.keys == @anskey.keys

（嗯。我可能刚刚回答了我自己的问题）

然后设置....

my_answer_is = @anskey.value

希望这更清楚。

原始“问题”如下：

辛苦了一天，屏幕有点疲劳……

我有这个...

str = [:wm24]

想说...

@anskey[:wm24]

这是错误的..

@anskey[str]

什么是正确的？

@anskey[?]

Answer 1

您可以将数组中的第一个元素传递给它，如下所示：

@anskey[str.first]

或者，如果您想根据其索引（数组中的位置）访问元素，则从零开始计数。所以在这种情况下：

@anskey[str[0]]