1

为什么我不能使用如下所示的外部映射将“类型”属性覆盖为非瞬态?当我序列化时,我没有看到“类型”元素。

public class PhoneNumber
{
    private String type;

    @XmlTransient
    public String getType()
    {
        return type;
    }

    //other properties
}

我使用“xml-attribute”指定了“type”,希望这将优先于注释,但它不起作用。

<java-type name="PhoneNumber">
         <java-attributes>
            <xml-attribute java-attribute="type" />
            <xml-value java-attribute="number" />
         </java-attributes>
</java-type>
4

1 回答 1

1

你似乎遇到了一个错误。您可以使用以下链接跟踪我们在此问题上的进展:

解决方法

PhoneNumber您可以指定该类应使用字段访问权限。

    <java-type name="PhoneNumber" xml-accessor-type="FIELD">
        <java-attributes>
            <xml-attribute java-attribute="type" />
            <xml-value java-attribute="number"/>
        </java-attributes>
    </java-type>

完整示例

电话号码

package forum11991936;

import javax.xml.bind.annotation.XmlTransient;

public class PhoneNumber {
    private String type;
    private String number;

    @XmlTransient
    public String getType() {
        return type;
    }
    public void setType(String type) {
        this.type = type;
    }
    public String getNumber() {
        return number;
    }
    public void setNumber(String number) {
        this.number = number;
    }

}

oxm.xml

<?xml version="1.0" encoding="UTF-8"?>
<xml-bindings xmlns="http://www.eclipse.org/eclipselink/xsds/persistence/oxm"
    package-name="forum11991936">
    <java-types>
        <java-type name="PhoneNumber" xml-accessor-type="FIELD">
            <xml-root-element name="phone-number"/>
            <java-attributes>
                <xml-attribute java-attribute="type" />
                <xml-value java-attribute="number"/>
            </java-attributes>
        </java-type>
    </java-types>
</xml-bindings>

jaxb.properties

javax.xml.bind.context.factory=org.eclipse.persistence.jaxb.JAXBContextFactory

演示

package forum11991936;

import java.util.*;
import javax.xml.bind.JAXBContext;
import javax.xml.bind.Marshaller;

import org.eclipse.persistence.jaxb.JAXBContextProperties;

public class Demo {

    public static void main(String[] args) throws Exception {
        Map<String, Object> properties = new HashMap<String, Object>();
        properties.put(JAXBContextProperties.OXM_METADATA_SOURCE, "forum11991936/oxm.xml");
        JAXBContext jc = JAXBContext.newInstance(new Class[] {PhoneNumber.class}, properties);

        PhoneNumber pn = new PhoneNumber();
        pn.setType("cell");
        pn.setNumber("555-1111");

        Marshaller marshaller = jc.createMarshaller();
        marshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true);
        marshaller.marshal(pn, System.out);
    }
}

输出

<?xml version="1.0" encoding="UTF-8"?>
<phone-number type="cell">555-1111</phone-number>
于 2012-08-16T20:59:42.713 回答