9

在无法假定 HTTPS 可用的情况下，我想确保 Android 应用程序和 C# ASP.NET 服务器之间的消息隐私。

我想使用 RSA 加密一个对称密钥，该密钥在第一次联系服务器时从 Android 设备传输。

RSA 密钥对已在服务器上生成，私钥保存在服务器上。密钥对是在 C# 中使用以下命令生成的：

// Create a new instance of RSACryptoServiceProvider
RSACryptoServiceProvider rsa = new RSACryptoServiceProvider(2048);
// Ensure that the key doesn't get persisted
rsa.PersistKeyInCsp = false;
RSAParameters parameters = rsa.ExportParameters(false);
string modulus = Convert.ToBase64String(parameters.Modulus);
string exponent = Convert.ToBase64String(parameters.Exponent);
string xmlKeys = rsa.ToXmlString(true);

尝试通过硬编码（从 Visual Studio 复制到 Eclipse）嵌入公钥是行不通的。该代码在 rsaCipher.doFinal() 方法调用中引发 org.bouncycastle.crypto.DataLengthException: input too large for RSA cipher。 

// Generate a new AES key
byte[] key = null;
try {
    KeyGenerator keygen = KeyGenerator.getInstance("AES");
    keygen.init(128);            
    key = keygen.generateKey().getEncoded();
}
catch (NoSuchAlgorithmException e) {}

// Set up modulus and exponent
String mod = "qgx5606ADkXRxndzurIRa5GDxzDYg5Xajeym7I8BXG1HBSzaaGmX+rjQfZK1h4JtQU+Xaowsc81mgJU8+gwneQa56r1bl6/5jFue4FsdXKfpau5az8rY2SAHKcOeyHAOsT9ZqcNa1x6cL/jl9P3cBtOzMk51Hk/w6VNoQ5JJo/0m/eAJzlhVKr2xbOYFhd0xp3qUgRuK8TN4TsSvfc+R1LOWc8+3H22Zj3vhBxSqSgeXxdxi7ThiGiAl6HUwMf8ph7FHNJvoUQq+QPL6dx77pu6xVFiHv1JOfpbKcOubn0VSPLYKY3QPKCzNMYQ6pxUDqzpGtydHR1xaX5K0FGTraw==";

String ex = "AQAB";
BigInteger modulus = new BigInteger(Base64.decode(mod, Base64.DEFAULT));
BigInteger exponent = new BigInteger(Base64.decode(ex, Base64.DEFAULT));

// Encrypt the AES key
PublicKey pubKey;
byte[] cipherData;
try {
    pubKey = KeyFactory.getInstance("RSA").generatePublic(new RSAPublicKeySpe(modulus, exponent));
    Cipher rsaCipher = Cipher.getInstance("RSA/ECB/PKCS1Padding");     
    rsaCipher.init(Cipher.ENCRYPT_MODE, pubKey);
    // The following line fails with:
    // org.bouncycastle.crypto.DataLengthException
    cipherData = rsaCipher.doFinal(key);     
}
catch (InvalidKeySpecException e) {}
catch (NoSuchAlgorithmException e) {}
catch (InvalidKeyException e) {}
catch (NoSuchPaddingException e) {}
catch (BadPaddingException e) {}
catch (IllegalBlockSizeException e) {}

我怀疑我错误地解码了模数字符串，因为在 Android 中生成公钥会成功加密密钥。我使用了这段代码：

KeyPairGenerator kpg = KeyPairGenerator.getInstance("RSA");     
kpg.initialize(1024);     
KeyPair kpa = kpg.genKeyPair();     
pubKey = kpa.getPublic();

那么，我做错了什么？

4

1 回答 1

7

Try using new BigInteger(1, modulus). BigIntegers are signed and as the modulus starts with the first bit set to 1, it will always be interpreted as a negative number.

于 2012-08-16T16:51:06.727 回答