python - 如何在 Python 上使用正则表达式删除括号？

Question

我有这样的字符串：

Alex Jatt, (alex.jatt@domain.com)

amd 我正在尝试使用正则表达式仅提取电子邮件地址，如下所示：

p = re.search('\((.*?)\)', c)

但 print p 命令打印（alex.jatt@domain.com）

如何修改此正则表达式以摆脱括号？

Answer 1

加入你也可以做到..

a= ''.join(c for c in a if c not in '()')

或使用正则表达式..

In[20]: import re

In[21]: name= re.sub('[()]', '', a)

In [22]: name
Out[22]: 'Alex Jatt, alex.jatt@domain.com'

Answer 2

没有regex解决方案：

>>> strs="Alex Jatt, (alex.jatt@domain.com)"
>>> strs.split(',')[1].strip().strip("()")
'alex.jatt@domain.com'

Answer 3

re.search允许您将匹配的组从正则表达式匹配中提取出来。在您的情况下，您可能希望用于p.group(1)提取第一个带括号的匹配项，它应该是您拥有的正则表达式中的电子邮件。

Answer 4

use a look ahead and a look behind to make sure that the parenthesis are there, but to prevent you from capturing them.

p = re.search('(?<=\().*?(?=\))', c)

or you could just access the capture group instead of the whole regex.

p = re.search('\((.*?)\)', c).group(1)

either way would work.

Answer 5

I think you've been changing the code before pasting it in here.

If I do:

>>> import re
>>> c="Alex Jatt, (alex.jatt@domain.com)"
>>> p = re.search('\((.*?)\)', c)
>>> print p
<_sre.SRE_Match object at 0x10bd68af8>

You want to look at the groups:

>>> import re
>>> c="Alex Jatt, (alex.jatt@domain.com)"
>>> p = re.search('\((.*?)\)', c)
>>> print p.groups()[0]
alex.jatt@domain.com