I have a url, "localhost/test/http://myimage.com/" (I'm passing myimage.com, because it's hosted on another site and I'm accessing it via an api) my question is how do I go about encoding the image portion of the URL? I thought about doing a gsub on the '.' and '/' and then gsubing them back, but I'm wondering if there's an easier way. Thanks for your help.
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148 次
2 回答
4
你可以使用URI::encode_www_form_component(str)和URI::decode_www_form_component
检查：http ://www.ruby-doc.org/stdlib-1.9.3/libdoc/uri/rdoc/URI.html
于 2012-08-15T02:15:17.377 回答
1
您可以使用 uri 库来转义和取消转义 url
require 'uri'
escaped = URI.escape(data, Regexp.new("[^#{URI::PATTERN::UNRESERVED}]"))
你可以用
original = URI.unescape(escaped)
于 2012-08-15T02:33:01.120 回答