2

我收到以下错误ExecuteNonQuery()

"String or binary data would be truncated. The statement has been terminated."

问题是要发送的变量比数据库中的变量大。我正在使用以下代码:

      protected void GridView1_RowUpdating(object sender, GridViewUpdateEventArgs e)
    {
        //GridViewRow row = GridView1.SelectedRow;
        GridViewRow row = (GridViewRow)GridView1.Rows[e.RowIndex];
        var Username = (Label)row.FindControl("Label3");
        var Password = (Label)row.FindControl("Label4");
        var Email = (Label)row.FindControl("Label5");
       // var ID_Inscricao = ((Label)row.FindControl("Label1")).Text;
        var ID_Inscricao = ((Label)row.FindControl("Label1")).Text;


        SqlConnection sqlConn = new SqlConnection(ConfigurationManager.ConnectionStrings["FormacaoConnectionString"].ToString());
        SqlCommand sqlComm = new SqlCommand();


        sqlComm = sqlConn.CreateCommand();
        sqlComm.Parameters.Add("@Username", SqlDbType.Text);
        sqlComm.Parameters.Add("@Password", SqlDbType.Text);
        sqlComm.Parameters.Add("@Email", SqlDbType.Text);
        sqlComm.Parameters.Add("@ID_Inscricao", SqlDbType.Int);

        sqlComm.Parameters["@Username"].Value = Convert.ToString(Username);
        sqlComm.Parameters["@Password"].Value = Convert.ToString(Password);
        sqlComm.Parameters["@Email"].Value = Convert.ToString(Email);
        sqlComm.Parameters["@ID_Inscricao"].Value = Convert.ToInt32(ID_Inscricao);

        string sql = "INSERT INTO Utilizadores (Username, Password, Email, ID_Inscricao) VALUES (@Username, @Password, @Email, @ID_Inscricao)";
        sqlComm.CommandText = sql;
        sqlConn.Open();
        sqlComm.ExecuteNonQuery();
        sqlConn.Close();
    }
4

3 回答 3

6

当您尝试将某些内容插入对于该列来说太长的列时,就会发生这种情况。

例如,当您有一列VARCHAR(10)并尝试插入值时"ABCDEFGHIJKLMNOP"。这将导致数据被截断并产生错误。

我不知道在您的情况下它是哪一列,但它必须是Username,PasswordEmail.

于 2012-08-14T14:24:33.160 回答
0

问题是您尝试填充的数据库中的数据类型小于您传递的值之一。您需要检查每个参数@Username、@Password 和@Email,并查看哪个参数大于数据库数据类型。然后您可以根据需要增加数据库中数据类型的大小,或者在发送前修剪参数值。

于 2012-08-14T14:27:53.903 回答
-1
 Dim qry As String
        qry = "inserg into Table1 values('" & TextBox1.Text & "'+'" & TextBox2.Text & "'+'" & DropDownList1.Text & "'+'" & DropDownList2.Text & "'+'" & TextBox4.Text & "'+'" & TextBox5.Text & "'+'" & RadioButtonList1.Text & "'+'" & RadioButton1.Text & "'+'" & RadioButtonList2.Text & "'+'" & CheckBoxList1.Text & "'+'" & TextBox6.Text & "'+'" & TextBox7.Text & "'+'" & TextBox8.Text & "'+'" & TextBox9.Text & "'+'" & TextBox10.Text & "'+'" & RadioButtonList3.Text & "'"
        Dim cn As New OleDbConnection("Provider=Microsoft.Jet.OLEDB.4.0;Data Source=C:\Documents and Settings\MCALab\My Documents\net.mdb")
        Dim cmd As New OleDbCommand(qry, cn)
        cn.Open()
        **cmd.ExecuteNonQuery()**this line have error please any one know mean debug it.

        cn.Close()
于 2013-07-22T09:26:29.543 回答