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我遇到了这个How Do I Sequentially Number Records in an Access Query 以便根据我发布的这个stackoverflow 问题（我从来没有做我想要做的事情）做我想做的事情，但每次我尝试将 AS Counter 添加到我得到的查询中

The expression you entered contains invalid syntax
You may have entered an operand without an operator

使用以下 sql：

SELECT Maintable.NumBR, Maintable.*, [Ehow] AS Expr1
FROM Maintable
WHERE (((Maintable.[NumBR])="" 
  Or (Maintable.[NumBR]) Like "3101" 
  Or (Maintable.[NumBR]) Like "3541" 
  Or (Maintable.[NumBR]) Like "4381" 
  Or (Maintable.[NumBR]) Like "AS3281" 
  Or (Maintable.[NumBR]) Like "4260" 
  Or (Maintable.[NumBR]) Like "4315" 
  Or (Maintable.[NumBR]) Like "4330" 
  Or (Maintable.[NumBR]) Like "4382" 
  Or (Maintable.[NumBR]) Like "9410" 
  Or (Maintable.[NumBR]) Like "9570" 
  Or (Maintable.[NumBR]) Like "AS3710" 
  Or (Maintable.[NumBR]) Like "AS4450" 
  Or (Maintable.[NumBR]) Like "K400" 
  Or (Maintable.[NumBR]) Like "3100" 
  Or (Maintable.[NumBR]) Like "3130" 
  Or (Maintable.[NumBR]) Like "3280" 
  Or (Maintable.[NumBR]) Like "3495" 
  Or (Maintable.[NumBR]) Like "3540" 
  Or (Maintable.[NumBR]) Like "3610" 
  Or (Maintable.[NumBR]) Like "3700" 
  Or (Maintable.[NumBR]) Like "4110" 
  Or (Maintable.[NumBR]) Like "4200")

AND (([Ehow])=DCount("[NumBR]","[Maintable]"," [NumBR] <= " & [NumBR])));

编辑上一个 stackoverflow 问题中提出的问题回答了这个问题。

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1 回答 1

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您的查询中不需要AS Counter短语。在链接的示例中，它被添加到SELECT语句中以别名列；在您的示例中，您正在使用WHERE子句，因此AS短语不会做任何事情（实际上是无效的）。

于 2012-08-13T19:53:33.290 回答