嗨,我正在自学android开发。首先,我使用apache http utils在android上实现了一个网络服务器,当localhost:8080
在模拟器上浏览时它会提供一个登录页面。
我想知道如何在 android 服务器端解析登录请求。此 Web 服务器根据请求的 Uri 动态提供内容。假设登录页面提交时,表单将发布到 /login.do,在localhost:8080
.
我已经为该操作注册了一个处理程序,如下所示。我想知道是否有一种方法可以在我的处理程序中解析请求主体并提供html
相应的服务。我在表单中只有一个字段可以解析password
。我只能得到就阅读请求标头而言。
任何正确方向的想法或指示将不胜感激。谢谢
import java.io.BufferedInputStream;
import java.io.ByteArrayOutputStream;
import java.io.IOException;
import java.io.InputStream;
import java.io.OutputStream;
import java.io.OutputStreamWriter;
import org.apache.http.HeaderElement;
import org.apache.http.HeaderElementIterator;
import org.apache.http.HttpEntity;
import org.apache.http.HttpException;
import org.apache.http.HttpRequest;
import org.apache.http.HttpResponse;
import org.apache.http.NameValuePair;
import org.apache.http.entity.ContentProducer;
import org.apache.http.entity.EntityTemplate;
import org.apache.http.message.BasicHeaderElementIterator;
import org.apache.http.protocol.HttpContext;
import org.apache.http.protocol.HttpRequestHandler;
import android.content.Context;
public class LoginHandler implements HttpRequestHandler {
private Context context = null;
String req;
public LoginHandler(Context context) {
this.context = context;
}
@Override
public void handle( final HttpRequest request, HttpResponse response,
HttpContext httpcontext) throws HttpException, IOException {
HttpEntity entity = new EntityTemplate(new ContentProducer() {
public void writeTo(final OutputStream outstream ) throws IOException {
String resp;
OutputStreamWriter writer = new OutputStreamWriter(outstream, "UTF-8");
HeaderIterator it = request.headerIterator();
while (it.hasNext())
{
System.out.println(it.next());
}
if (validateUser()==true)
resp = "<html><head></head><body><h1>Home<h1><p>Success."+req+"</p></body></html>";
else{
resp="<html><head></head><body><h1>Home<h1><p>Login Failed.</p></body></html>";}
writer.write(resp);
writer.flush();
}
});
response.setHeader("Content-Type", "text/html");
response.setEntity(entity);
}
boolean validateUser(){
boolean valid=false;
//if valid valid=true else valid=false
return valid;
}
}
输出如下:
08-15 15:54:22.112: I/Process(650): Sending signal. PID: 650 SIG: 9
08-15 15:54:27.532: I/HTTPSERVICE(662): Creating and starting httpService
08-15 15:54:27.542: I/Notification(662): Notification Shown
08-15 16:08:19.332: I/HTTPSERVICE(662): Destroying httpService
08-15 16:08:19.352: I/Notification(662): Notification Destroyed
08-15 16:20:14.852: I/HTTPSERVICE(690): Creating and starting httpService
08-15 16:20:14.862: I/Notification(690): Notification Shown
08-15 16:20:28.102: D/dalvikvm(690): GC freed 2292 objects / 135976 bytes in 157ms
08-15 16:20:28.872: I/Resources(690): Loaded time zone names for en_US in 3090ms.
08-15 16:20:28.882: I/global(690): Default buffer size used in BufferedReader constructor. It would be better to be explicit if an 8k-char buffer is required.
08-15 16:20:35.302: I/System.out(690): Host: localhost:8080
08-15 16:20:35.382: I/System.out(690): Accept-Encoding: gzip
08-15 16:20:35.422: I/System.out(690): Referer: http://localhost:8080/
08-15 16:20:35.422: I/System.out(690): Accept-Language: en-US
08-15 16:20:35.442: I/System.out(690): User-Agent: Mozilla/5.0 (Linux; U; Android 2.1-update1; en-us; sdk Build/ECLAIR) AppleWebKit/530.17 (KHTML, like Gecko) Version/4.0 Mobile Safari/530.17
08-15 16:20:35.472: I/System.out(690): Origin: http://localhost:8080
08-15 16:20:35.512: I/System.out(690): Accept: application/xml,application/xhtml+xml,text/html;q=0.9,text/plain;q=0.8,image/png,*/*;q=0.5
08-15 16:20:35.533: I/System.out(690): Content-Type: application/x-www-form-urlencoded
08-15 16:20:35.562: I/System.out(690): Accept-Charset: utf-8, iso-8859-1,utf-16,*;q=0.7
08-15 16:20:35.599: I/System.out(690): Content-Length: 25
我在 apache 网站上找不到任何适用于我的案例的资源。是否可以直接从 url 读取 requestbody?