-1 
        try{
            $pdo = new PDO("mysql:host=localhost;dbname=name", 'user', 'pass');
            $pdo->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
            $statement = "SELECT id FROM users WHERE email LIKE ?";
            $stmt = $pdo->prepare($statement);
            $stmt->bindParam(1, htmlspecialchars($this->params['email']), PDO::PARAM_STR);
            $stmt->setFetchMode(PDO::FETCH_ASSOC);
            $row = $stmt->fetch();

        }catch (PDOException $e) {
            echo $e;
        }

        print_r($row[0]['id']);

        if(is_int($row[0]) > 0) {
            throw new Exception();
        } elseif(is_int($row[0]) > 0) {
            //Generating encryption
            $crypt = mcrypt_module_open(MCRYPT_RIJNDAEL_256, '', MCRYPT_MODE_CBC, '');
            $iv = mcrypt_create_iv(32, MCRYPT_RAND);
            $key = mcrypt_create_iv(32, MCRYPT_RAND);
            $password = mcrypt_create_iv(12, MCRYPT_RAND);
            mcrypt_generic_init($crypt, $key, $iv);
            $crypted = mcrypt_generic($crypt, $password);


            $activation = mcrypt_create_iv(128, MCRYPT_RAND);

            mcrypt_generic_deinit($crypt);




            try{
                $pdo = new PDO("mysql:host=localhost;dbname=name", 'user', 'pass');
                $pdo->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
                $statement = "INSERT INTO users(name, password, cryptokey, cryptovector, email, activation_code, active, usertype) values(?, ?, ?, ?, ?, ?, 0, ?); ";
                $stmt = $pdo->prepare($statement);
                $stmt->bindParam(1, mysql_real_escape_string($this->params['name']), PDO::PARAM_STR);
                $stmt->bindParam(2, $password, PDO::PARAM_STR);
                $stmt->bindParam(3, $key, PDO::PARAM_STR);
                $stmt->bindParam(4, $iv, PDO::PARAM_STR);
                $stmt->bindParam(5, mysql_real_escape_string($this->params['email']), PDO::PARAM_STR);
                $stmt->bindParam(6, $activation, PDO::PARAM_STR);
                $stmt->bindParam(7, mysql_real_escape_string($this->params['acctype']), PDO::PARAM_STR);

                $stmt = null;

            }catch (PDOException $e) {
                print_r($e);
            }


            $smarty = new Smarty();

            $smarty->assign('NAMES',$this->params['name']);
            $smarty->assign('UNIT', $this->params['acctype']);
            $smarty->assign('KEYPASS',$password);
            $smarty->assign('NAMES',$this->params['name']);
            $smarty->assign('ACTIVATION_LINK','https://localhost/profile.php?action=activate&key='.urlencode($activation).'&email='.urlencode($this->params['email']));

            $msgBody = $smarty->fetch('templates/default/mail.html');

            try {
                $mail = new PHPMailer();

                $mail->Host = "server";
                $mail->SMTPAuth = TRUE;
                $mail->Host = "server";
                $mail->Port = 25;
                $mail->Username = "email";
                $mail->Password = "password";

                $mail->AddAddress($this->params['email']);
                $mail->SetFrom('test@example', 'test Services');

                $mail->Subject = 'Confirm registration and login credentials.';
                $mail->MsgHTML($msgBody);    // attachment
                #$mail->Send();

                echo 'localhost/profile.php?action=verify&key='.base64_encode($activation).'&email='.urlencode($this->params['email']);
            } catch (phpmailerException $e) {
                #echo $e; //Pretty error messages from PHPMailer
                print_r($e);
            } catch (Exception $e) {
                echo $e; //Boring error messages from anything else!
                print_r($e);
            }


        }

    }

所以这是我的身份验证方法。__construct($arg1, $arg2); $arg1 获取操作，$arg2 是 $self::params 获取它需要的变量，在这种情况下是电子邮件名称和密码。它打印激活链接用于测试目的，当它打印时，我会在它后面看到 Array()。具有 isset($row) 的 if 语句没有执行它所具有的功能，因为它告诉我的脚本该行已设置。当我 print_r 它时，我什么都看不到...当 echo 我看到 Array( ).... 我使用 Zend 服务器 CE 和 PHP 5.4，我有一个结构如下的表：

id，-名称，-密码，-cryptokey，-cryptovector，-email，-activation_code，-active，-usertype
1，-J.Smith，-pwd，-key，-vector，-some@mail，-激活码， - 0, - 候选人

4

1 回答 1

1

您的代码中缺少$stmt->execute();。这是我现在在 Eclipse 中碰巧拥有的代码示例：

$sql="select id from users where userName=:userName";
$this->prepared = $this->mysqlAccess->con->prepare($sql, array(PDO::ATTR_CURSOR => PDO::CURSOR_FWDONLY));
$this->prepared->execute(array(':userName' => $this->username));

准备语句时，需要先执行它，然后才能查询结果。

于 2012-08-13T11:25:36.377 回答