4

我无法弄清楚这个错误：

*** Terminating app due to uncaught exception 'NSInvalidArgumentException', reason: '*** +[NSJSONSerialization writeJSONObject:toStream:options:error:]: Invalid top-level type in JSON write'

这与这段代码有关（基本上我正在创建一些 JSON 并将其发送到服务器）。我已经和服务器核对过socket是否打开了，就是这个！

NSDictionary *blobData = [NSDictionary dictionaryWithObjectsAndKeys:
                          sendString,@"string",
                          nil];
NSString *blobString = [[NSString alloc]
                        initWithData:[NSJSONSerialization dataWithJSONObject:blobData options:kNilOptions error:&error]
                        encoding:NSUTF8StringEncoding];
NSLog(@"Blob Created: %@", blobString);
NSDictionary *requestData = [NSDictionary dictionaryWithObjectsAndKeys:
                             @"send_string",@"request_type",
                             [NSNumber numberWithInt:0],@"security_level",
                             @"ios",@"device_type",
                             //No Email Provided, This is just for testing
                             blobData,@"blob",
                             nil];

NSData *JSONRequestData = NULL;
if ([NSJSONSerialization isValidJSONObject:requestData]) {
    NSLog(@"Proper JSON Object");
    JSONRequestData = [NSJSONSerialization dataWithJSONObject:requestData options:kNilOptions error:&error];
}
else {
    NSLog(@"requestData was not a proper JSON object");
    return FALSE;
}
NSLog(@"Error:%@",[[error userInfo] objectForKey:@"NSDebugDescription"]);
NSLog(@"Contents of JSONRequestData: %@",[[NSString alloc] initWithData:JSONRequestData encoding:NSUTF8StringEncoding]);
[NSJSONSerialization writeJSONObject:JSONRequestData toStream:outputStream options:0 error:&error];

我创建的 JSON 对象错了吗？也许我处理“blob”的方式有问题

这是我创建 JSONRequestData 后 NSLogs 打印的内容

{"security_level":"0","request_type":"send_string","device_type":"ios","blob":{"string":"hello"}}
4

1 回答 1

3

writeJSONObject期望您要发送的实际未序列化对象，因此在这种情况下，您希望将requestData对象传递给它，而不是JSONRequestData像：

NSJSONSerialization writeJSONObject:requestData toStream:outputStream options:0 error:&error];
于 2012-08-13T13:23:55.350 回答