c++ - 错误预期声明 c ++

Question

更新2：好吧，我修好了，原来这是一个简单的问题，半柱进入它不属于的地方，正在寻找完全错误的地方。

更新：删除一些注释修复了 cin cout 错误，现在唯一的错误应该是在左括号和右括号上的声明，并且一个出现在 else 语句中。

错误“预期声明”出现在函数 playeroneturn 的开始和结束 {} 以及函数中 if 语句的结束 } 中，也在 if 语句中 cin 和 cout 都给出错误“这个声明没有存储类或类型说明符”

#include "stdafx.h"
#include "iostream"
#include "ctime"
#include "cstdlib"
#include "string"

//prototype function declaration from stackoverflow.com/questions/2575153/must-declare-function-prototype-in-c
int help(int menu);
int start(int menu);
int oneplaymode();
int playeroneturn();
int playertwoturn();

//function start is called to display the games menu screen
int start(int menu)
{
    using std::cout;
    using std::cin;
    using std::endl;
    cout << "#########################################################################" << endl;
    cout << "#\t\t\t\t\t\t\t\t\t#" << endl << "#\t\t\t\t    PIGS\t\t\t\t#" << endl << "#\t\t\t\t\t\t\t\t\t#" << endl << "#\t\t\t\t\t\t\t\t\t#" << endl << "#\t\t\t\t1. 1 Player\t\t\t\t#" << endl << "#\t\t\t\t\t\t\t\t\t#" << endl << "#\t\t\t\t2. 2 Player\t\t\t\t#" << endl << "#\t\t\t\t\t\t\t\t\t#" << endl << "#\t\t\t\t3. help\t\t\t\t\t#" << endl << "#\t\t\t\t\t\t\t\t\t#" << endl << "#\t\t\t\t\t\t\t\t\t#" << endl << "#\t\t\t\t\t\t\t\t\t#" << endl << "#\t\t\t\t\t\t\t\t\t#" << endl << "#\t\t\t\t\t\t\t\t\t#" << endl << "#\t\t\t\t\t\t\t\t\t#" << endl << "#\t\t\t\t\t\t\t\t\t#" << endl << "#\t\t\t\t\t\t\t\t\t#" << endl<< "#\t\t\t\t\t\t\t\t\t#" << endl<< "#\t\t\t\t\t\t\t\t\t#" << endl<< "#\t\t\t\t\t\t\t\t\t#" << endl<< "#\t\t\t\t\t\t\t\t\t#" << endl<< "#\t\t\t\t\t\t\t\t\t#" << endl;
    cout << "#########################################################################" << endl;
    cout << "enter number for your selection: ";
    cin >> menu;
    if(menu == 1)
    {
        cout << "single-player not yet implemented" << endl;

    }
    else if(menu == 2)
    {
    int twoplayermode();
    }
    else if(menu == 3)
    {
    help(menu);
    }
    else
    {
    cout << "Error: Please choose a valid option" << endl;

    start(menu); 

    }
return(menu);
}

int help(int menu)
{
    using std::cout;
    using std::endl;    
    cout << "#########################################################################" << endl;
    cout << "#\t\t\t\t\t\t\t\t\t#" << endl << "#\t\t\t\t HELP\t\t\t\t\t#" << endl << "#\t\t\t\t\t\t\t\t\t#" << endl << "#  The objective of pigs is to be the first to score 100.\t\t#" << endl << "#  Each turn you must roll a die then pass or roll again.\t\t#" << endl << "#  You must then choose to ROLL again or END your turn.\t\t\t#" << endl << "#  At the end of your turn your total is added to your score.\t\t#" << endl << "#  However if you roll a 1 your turn ends and you score 0.\t\t#" << endl << "#\t\t\t\t\t\t\t\t\t#" << endl << "#\t\t\t\t\t\t\t\t\t#" << endl << "#\t\t\t\t\t\t\t\t\t#" << endl << "#\t\t\t\t\t\t\t\t\t#" << endl << "#\t\t\t\t\t\t\t\t\t#" << endl << "#\t\t\t\t\t\t\t\t\t#" << endl << "#\t\t\t\t\t\t\t\t\t#" << endl << "#\t\t\t\t\t\t\t\t\t#" << endl << "#\t\t\t\t\t\t\t\t\t#" << endl<< "#\t\t\t\t\t\t\t\t\t#" << endl<< "#\t\t\t\t\t\t\t\t\t#" << endl<< "#\t\t\t\t\t\t\t\t\t#" << endl<< "#\t\t\t\t\t\t\t\t\t#" << endl<< "#\t\t\t\t\t\t\t\t\t#" << endl;
    cout << "#########################################################################" << endl;
    system("pause");
    start(menu);
    return 0;
}

int playeroneturn(int p1score);
{
    using namespace std;
    using std::cout;
    using std::cin;
    using std::endl;
    using std::srand;
    using std::rand;
    using std::time;
    using std::string;
    srand((unsigned int)time(0)); 
    int roll = 0;
    int p1score = 0;
    string reroll = "roll";
    while(reroll == "roll") 
    {
        roll = 1 + (rand() % 6);
            if(roll > 1)
            {
                p1score = p1score+roll;
                // using " in a string msdn.microsoft.com/en-us/library/267k4fw5.aspx
                cout << "You rolled a " << roll << endl << "Type roll to roll again or end to end your turn."; // error on cout this declaraton has no storage class or type specifier and error on first << expected a ;
                cin >>  reroll; 
            }
            else 
            { 
                cout >> "Bad luck! you rolled a 1, your turn is over and you score nothing!"
                p1score = 0; 
                reroll = end;
            }
    }
    return p1score; 
}

Answer 1

I see several issues (from my comment):

• you cannot have statements like 1 + (rand() % 6); = roll. What is this supposed to do? If you want roll to be 1 + (rand() % 6);, write it roll = 1 + (rand() % 6);
• you cannot use continue as variable, it's reserved keyword
• you cannot mix >> and << when using cout. Use only <<.
• p1score is not initialized (it's not compiler's error, but still - you use it (in the body of the if-statement, where the first condition (if(roll > 1)) is true) without being initialized, so you'll get garbage value
• have you included #include <string>?

• you don't have using std::string and if you don't have using namespace std;, you'll have a compiler error for this, too.

• waiting for an answer - what is before the first {.

---

EDIT: Looking at you edit, you need to do some other changes:

• first, the definition of playeroneturn is wrong: int playeroneturn(int p1score); { ... } <- remove ; before the function's body
• note, that in playeroneturn, int p1score = 0; shadows the parameter of the function, it has the same name
• again in playeroneturn - cout must be used with <<, not with >>
• a ';' must be added after the wrong cout (from the previous point)
• in playeroneturn (again), reroll = end; is bad - what is this end, it's not defined nowhere.

Answer 2

continue是关键字，不能用作变量名。

Answer 3

while(continue == "roll")
{
    1 + (rand() % 6); = roll //<--- what is this? no ; and no l value
        if(roll > 1)

分号和左值在哪里？

Answer 4

continue is a keyword / reserved word. and hence it should not be used as a variable name or other literal specification.For feeling the difference just rename the variable 'continue' to 'continue1' and see the error go. Hope this will help.