3

我需要检查用户何时按下某个键并释放它。如果有钥匙，我会做一次。

我使用击键来获取我想要关联动作的按钮。我还使用信号量来克服这个问题，但它看起来很疯狂

我的代码：`

InputMap inputMap = jPanel1.getInputMap();
KeyStroke keyPressed = KeyStroke.getKeyStroke(KeyEvent.VK_1, 0, false);
KeyStroke keyReleased = KeyStroke.getKeyStroke(KeyEvent.VK_1, 0, true);
//------------------------------------------
jPanel1.getActionMap().put("_1000Press", _1000Press);
inputMap.put(keyPressed, "_1000Press");
jPanel1.getActionMap().put("_1000Release", _1000Release);
inputMap.put(keyReleased, "_1000Release");
public Action _1000Press = new AbstractAction() {

    @Override
    public void actionPerformed(ActionEvent e) {
        if(!one){
            // do some thing
            one = true;
            System.out.println(one);
        }
    }
};
public Action _1000Release = new AbstractAction() {

    @Override
    public void actionPerformed(ActionEvent e) {
        one = false;
        System.out.println(one);
    }
};

`

当我按下“1”键并按住它时，它会打印：false true false true false true

提前致谢。

4

2 回答 2

1

这对我来说很好

InputMap im = getInputMap();
ActionMap am = getActionMap();

im.put(KeyStroke.getKeyStroke(KeyEvent.VK_1, 0, false), "Press");
im.put(KeyStroke.getKeyStroke(KeyEvent.VK_1, 0, true), "Release");

am.put("Press", new AbstractAction() {

    @Override
    public void actionPerformed(ActionEvent e) {

        if (!pressed) {

            pressed = true;
            System.out.println("press");

        }

    }

});

am.put("Release", new AbstractAction() {

    @Override
    public void actionPerformed(ActionEvent e) {

        if (pressed) {

            pressed = false;
            System.out.println("release");

        }

    }

});

只是为了确保我这样做

am.put("Release", new AbstractAction() {

    @Override
    public void actionPerformed(ActionEvent e) {

        pressed = false;
        System.out.println("release");

    }

});

它仍然有效

press当我按住 1 时打印，然后在release我释放键时打印。那是我得到的唯一输出

已更新完整代码

public class TestPane extends JPanel {

    private boolean pressed;

    public TestPane() {

        InputMap im = getInputMap();
        ActionMap am = getActionMap();

        im.put(KeyStroke.getKeyStroke(KeyEvent.VK_1, 0, false), "Press");
        im.put(KeyStroke.getKeyStroke(KeyEvent.VK_1, 0, true), "Release");

        am.put("Press", new AbstractAction() {

            @Override
            public void actionPerformed(ActionEvent e) {

                if (!pressed) {

                    pressed = true;
                    System.out.println("press");

                }

            }

        });

        am.put("Release", new AbstractAction() {

            @Override
            public void actionPerformed(ActionEvent e) {

                if (pressed) {

                    pressed = false;
                    System.out.println("release");

                }

            }

        });

    }

}
于 2012-08-11T20:56:55.873 回答
1

我不相信你可以在 Linux 中实现你所需要的，因为操作系统不断地向 JVM 发出按下/释放信号。

看

于 2012-08-11T23:12:44.773 回答