嗨,伙计们,我有这个脚本,但显然我没有使用 foreach 对我想知道是否可以将这两个请求结合起来作为一个请求
$url = "http://api.website.com/1.0/country?source=ballsche&programid=5380&campaignid=100000";
$ch = curl_init();
$timeout = 0;
curl_setopt($ch, CURLOPT_URL, $url);
curl_setopt($ch, CURLOPT_HEADER, 0);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($ch, CURLOPT_CONNECTTIMEOUT, $timeout);
$rawdata = curl_exec($ch);
curl_close($ch);
$array = json_decode($rawdata,true);
foreach($array as $obj) {
$country = $obj['country'];
$countrycode = $obj['countryCode'];
}
foreach($countrycode as $did) {
$wgurl = "http://api.website.com/1.0/city?source=ballsche&programid=5380&campaignid=100000&country-code=$did";
$wgch = curl_init();
$wgtimeout = 0;
curl_setopt($wgch, CURLOPT_URL, $wgurl);
curl_setopt($wgch, CURLOPT_HEADER, 0);
curl_setopt($wgch, CURLOPT_RETURNTRANSFER, 1);
curl_setopt($wgch, CURLOPT_CONNECTTIMEOUT, $wgtimeout);
$wgrawdata = curl_exec($wgch);
curl_close($wgch);
$wgarray = json_decode($wgrawdata,true);
}
foreach($wgarray as $wgobj) {
$city = $wgobj['city'];
$citycode = $wgobj['cityCode'];
if($city){
$sql = "INSERT INTO `pt_city` (city, citycode) VALUES ('$city', '$citycode')";
database_queryModify($sql,$result);
}else{
echo "dint work";
}
}
必须有一个简单的方法来做到这一点我猜想从数据中创建另一个数组但我不能完全正确我不断收到错误我尝试过这个和其他一些事情我的问题是我需要循环通过县代码并提出请求那里的代码有 150 个请求,我需要循环获取所有城市信息,并且对于每个请求,我需要解码返回的 json 并将其插入到我的城市表中