c++ - 路径树到树结构

Question

您好，假设您有普通的 unix 路径树作为输入（作为字符串）。

root 0
root/file1.txt 1
root/file2.txt 2
root/folder1 3
root/folder1/file3.txt 4
root/folder1/file4.txt 5
e.t.c.

将此字符串转换为树数据结构的更好方法是什么？

Answer 1

Now i use simple tree representation, created by myself

template<typename T>
class TreeNode
{
public:
    TreeNode() {};

    TreeNode(T)
    {
        value = T;
    }

    TreeNode(const T& value)
        : Value(value)
    {
    }

    T Value;
    vector<TreeNode<T>*> Children;
};

I don't really understand Gir's algorithm (posted above). But i suppose the solution must be the following:

1. Get a root node, set depth_level = 0
3. set support_node = root_node
4. for each path line
5.     determine the quantity of slashes "/", key and file(folder) name

so for example in string root/folder1/file4.txt 5, num of slashes = 2 filename = file4.txt, key = 5
       create current_node
6.     if num_of_slashes == level + 2
7.          set support_node = current_node
8.     if num_of_slashes == level + 1
9.          add children to support_node
10.    And after that we must remember all ancestors,  going down to leaves. Cuz we can  return to any ancestor.

For me this algorithm seems to be really complicated. I don't understand algorithm, posted above, maybe it is possible to clarify this question? Maybe the structure i use to store the tree isn't the best one?

Answer 2

像这样的东西：

为“\”创建一个根节点

node=root;
token=getNextToken(inputString);
while (token){
 if (!node.childExist(token)) node.createChild(token)
 node=node.Child(token)
 token=getNextToken(inputString);
}