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试图允许用户输入文本区域,但如果看到某个单词,我希望光标停止,直到该单词被删除。

我找到了这个词,但我找不到让光标停止的方法。

关于我如何在 javascript 中执行此操作的任何想法

 $(function() {
            $('#ideacomment').bind('keyup', function(e){
                var characterLimit = 300;
                charactersUsed = $(this).val().length;

                if(charactersUsed > characterLimit){
                    charactersUsed = characterLimit;
                    $(this).val($(this).val().substr(0, characterLimit));
                    $(this).scrollTop($(this)[0].scrollHeight);
                }
                var charactersRemaining = characterLimit - charactersUsed;
                $('#remainingCharacters').html(charactersRemaining);

                 var words = $('#ideacomment').val().split(/\b[\s,\.-:;]*/);
                 var wordcount = words.length;
                 var nonewords = new Array("f**k", "you");
                 var nonewordcount = nonewords.length;
                //console.log(nonewordcount + ' is the count');

                for(var i = 0; i < wordcount; i++) {

                    for(var t = 0; t < nonewordcount; t++) {
                        if(words[i] == nonewords[t]) {
                            message('No swearing please! <br><br> This post will not succeed!<br><br> Please remove it before you continue!', '430');
                            }
                        }
            }
            });


      });

上面的代码计算字符数并检查每个单词。我是否愿意并且我尝试过但没有成功是让它好像空间用完了。但是我一直无法使用与限制器相同的代码来实现它?

这是新代码。但仍然无法正常工作:

        $(function() {
            $('#ideacomment').bind('keyup', function(e){
                var characterLimit = 300;
                charactersUsed = $(this).val().length;

                if(charactersUsed > characterLimit){
                    charactersUsed = characterLimit;
                    $(this).val($(this).val().substr(0, characterLimit));
                    $(this).scrollTop($(this)[0].scrollHeight);
                }
                var charactersRemaining = characterLimit - charactersUsed;
                $('#remainingCharacters').html(charactersRemaining);

                 var nonewords = new Array("hey", "you");
                 var nonewordcount = nonewords.length;
                 for(var t = 0; t < nonewordcount; t++) {
                     if ($(this).val().indexOf(nonewords[t]) != -1) {
                        message('No swearing please! <br><br> This post will not succeed!<br><br> Please remove it before you continue!', '430');
                         var keycode = e.charCode || e.keyCode;
                            console.log(keycode);
                            if (keycode !== 8 && keycode !== 46)
                                return false;
                                }   
    }

                 });
            });
4

1 回答 1

3

您可以检查正在按下哪个键,如果它不是 aBackspace或则阻止它Delete。这是一个简化的示例:

$(function() {
    $('#textbox').keydown(function(e) {
        if ($(this).val().indexOf('test') != -1) {
            var keycode = e.charCode || e.keyCode;
            if (keycode !== 8 && keycode !== 46)
                return false;
        }
    });
});​

jsFiddle 演示

由于您似乎已经有了文本检查和通知部分,所以您真正缺少的只是按键阻止部分。

于 2012-08-10T20:13:02.187 回答