0

我正在使用 Python 通过 RS232 串行对话从仪器传输数据。数据以 ASCII 格式输入。例如，这是我使用Python从仪器中得到的 ASCII 码：

'\x02S20390908127F010102F3004000900300000000000000000000000000000300A500000000000202020202020206070505050505050000000707070707070707020700000000000000000000000000000000000000008000800089237A0715047E000000000000000000000000000000000000000000000000000000000000000000000000005350374646303030\x1732'

使用超级终端（Docklight）的相同数据传输给了我这个，以下是我在超级终端中得到的十六进制表示：

02 53 31 38 33 38 30 39 30 38 31 32 37 46 30 31 30 31 30 32 46 33 30 30 34 30 30 30 39 30 30 33 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 33 30 30 41 35 30 30 30 30 30 30 30 30 30 30 30 32 30 32 30 32 30 32 30 32 30 32 30 32 30 36 30 37 30 35 30 35 30 35 30 35 30 35 30 35 30 30 30 30 30 30 30 37 30 37 30 37 30 37 30 37 30 37 30 37 30 37 30 32 30 37 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 38 30 30 30 38 30 30 30 38 39 32 33 37 41 30 37 31 35 30 34 37 45 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 35 33 35 30 33 37 34 36 34 36 33 30 33 30 33 30 17 33 38

我的问题是，我如何使用Python从我得到的 ascii 数据中获得相同的十六进制表示。说到这种东西，我是个菜鸟。先感谢您。

4

2 回答 2

1

说明：将每个字符转换为字节，ord然后将其格式化为两位十六进制数并将其输入列表。然后使用空格作为分隔符加入列表。

>>> ll = ["%02X" % (ord(x)) for x in '\x02S20390908127F010102F3004000900300000000000000000000000000000300A500000000000202020202020206070505050505050000000707070707070707020700000000000000000000000000000000000000008000800089237A0715047E000000000000000000000000000000000000000000000000000000000000000000000000005350374646303030\x1732']
>>> ll           #as a list
['02', '53', '32', '30', '33', '39', '30', '39', '30', '38', '31', '32', '37', '46', '30', '31', '30', '31', '30', '32', '46', '33', '30', '30', '34', '30', '30', '30', '39', '30', '30', '33', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '33', '30', '30', '41', '35', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '32', '30', '32', '30', '32', '30', '32', '30', '32', '30', '32', '30', '32', '30', '36', '30', '37', '30', '35', '30', '35', '30', '35', '30', '35', '30', '35', '30', '35', '30', '30', '30', '30', '30', '30', '30', '37', '30', '37', '30', '37', '30', '37', '30', '37', '30', '37', '30', '37', '30', '37', '30', '32', '30', '37', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '38', '30', '30', '30', '38', '30', '30', '30', '38', '39', '32', '33', '37', '41', '30', '37', '31', '35', '30', '34', '37', '45', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '30', '35', '33', '35', '30', '33', '37', '34', '36', '34', '36', '33', '30', '33', '30', '33', '30', '17', '33', '32']
>>> ' '.join(ll) # as a string
'02 53 32 30 33 39 30 39 30 38 31 32 37 46 30 31 30 31 30 32 46 33 30 30 34 30 30 30 39 30 30 33 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 33 30 30 41 35 30 30 30 30 30 30 30 30 30 30 30 32 30 32 30 32 30 32 30 32 30 32 30 32 30 36 30 37 30 35 30 35 30 35 30 35 30 35 30 35 30 30 30 30 30 30 30 37 30 37 30 37 30 37 30 37 30 37 30 37 30 37 30 32 30 37 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 38 30 30 30 38 30 30 30 38 39 32 33 37 41 30 37 31 35 30 34 37 45 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 30 35 33 35 30 33 37 34 36 34 36 33 30 33 30 33 30 17 33 32'
于 2012-08-10T16:11:58.183 回答
0

这似乎是最简单的方法...

ascstr = 'x\02S20..."  #your string

#I think you need to get rid of the first 4 characters '\x02' looks like
#it is hex
ascstr = ascstr[4:] 
for c in mystring:
   hexstr = hexstr + hex(ord(c))[2:] + ' '
于 2012-08-10T16:16:07.690 回答