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我想发送 $c2=@'http://marvelconcepts.net/fb3/02.php?c='.$c.'&&'.'c1='.$c1; 在 02.php 上,当我得到 $C ON 02.php 时,它没有显示完整的网址

 <?php
$c='Flower';
$c1='http://aux.iconpedia.net/uploads/1337412470.png';
$c2=@'http://marvelconcepts.net/fb3/02.php?c='.$c.'&amp;&amp;'.'c1='.$c1;
?>
<a href='02.php?c=<?php echo $c; ?>&amp;c1=<?php echo $c1; ?>&amp;c2="<?php echo $c2; ?>"'>share</a>
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1 回答 1

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使用urlencodeurldecode

参考

http://php.net/manual/en/function.urlencode.php

http://www.php.net/manual/en/function.urldecode.php

于 2012-08-10T10:07:45.140 回答