3

有没有办法在运行时检查清单中声明了哪些广播接收器?

4

4 回答 4

3

使用PackageManager,您可以queryBroadcastReceivers()找出谁会响应特定Intent的 ,使用getInstalledPackages(),您可以找出每个包安装的接收器。

于 2012-08-10T00:14:57.147 回答
3

在 Activity 中,代码将与此类似:

// Query all packages that have the BroadcastReceivers...
Intent mainIntent = new Intent(Intent.ACTION_MAIN, null);
mainIntent.addCategory(Intent.CATEGORY_LAUNCHER);
PackageManager pm = getPackageManager();
final List<ResolveInfo> listPkgs = pm.queryBroadcast(mainIntent, 0);
if (listPkgs != null && listPkgs.size() > 0){
   for(ResolveInfo resInfo : listPkgs){
       // Now resInfo will contain the list of packages that has receivers...
   }
}
于 2012-08-10T00:40:08.243 回答
1

谢谢,但这不是我的意图......我想知道是否在运行时在运行的应用程序中声明了特定的接收器,并像这样实现它:

    private <Receiver extends CyborgReceiver<?>> boolean checkIfBroadcastReceiverIsRegisteredInManifest(Class<Receiver> receiverType) {
    PackageManager pm = application.getPackageManager();
    try {
        ActivityInfo info = pm.getReceiverInfo(new ComponentName(application, receiverType), PackageManager.GET_RECEIVERS);
        return info.enabled;
    } catch (NameNotFoundException e) {
        return false;
    }
}
于 2012-08-13T21:27:07.103 回答
0

传入应用程序对象作为第一个参数,(Application)context.GetApplicationContext()如果需要,您可以这样做,然后传入实现广播接收器类的类作为第二个参数,例如broadcastReceiver.class

public static boolean validateReceiverInManifest(Application application, Class receiverClass) throws PackageManager.NameNotFoundException {
    PackageManager pm = application.getPackageManager();
    String packageName = application.getPackageName();

    PackageInfo packageInfo = pm.getPackageInfo(packageName, PackageManager.GET_RECEIVERS);
    ActivityInfo[] receivers = packageInfo.receivers;
    String receiverClassName = receiverClass.getName();
    for (ActivityInfo activityInfo : receivers) {
        if (activityInfo.name.equals(receiverClassName)) {
            return true;
        }
    }
    return false;
}
于 2015-06-12T05:17:33.887 回答