12

我知道如何在 Windows 7 中获取今天的日期。这是我正在使用的命令:

%DATE:~6,4%%DATE:~3,2%%DATE:~0,2%

但我想昨天得到,我不知道如何。

4

4 回答 4

16

如果您仅限于 cmd.exe那么其他解决方案(尽管它们的大小)可能与您获得的一样好。但是,现代 Windows(例如您的 Win7)附带了许多其他工具,可以更轻松地完成这项工作。

只需创建一个 VBScriptyester.vbs脚本,如下所示:

d = date() - 1
wscript.echo year(d) * 10000 + month(d) * 100 + day(d)

然后你可以从你的cmd脚本中调用它:

for /f %%a in ('cscript //nologo yester.vbs') do set yesterday=%%a

并且yesterday变量将以yyyymmdd您想要的形式创建,供您操作。

于 2015-08-07T05:12:09.697 回答
8

找到了一个脚本,即使年份或月份发生变化Dos Yesterday Batch也能确保您获得前一天。

@echo off

set yyyy=

set $tok=1-3
for /f "tokens=1 delims=.:/-, " %%u in ('date /t') do set $d1=%%u
if "%$d1:~0,1%" GTR "9" set $tok=2-4
for /f "tokens=%$tok% delims=.:/-, " %%u in ('date /t') do (
for /f "skip=1 tokens=2-4 delims=/-,()." %%x in ('echo.^|date') do (
set %%x=%%u
set %%y=%%v
set %%z=%%w
set $d1=
set $tok=))

if "%yyyy%"=="" set yyyy=%yy%
if /I %yyyy% LSS 100 set /A yyyy=2000 + 1%yyyy% - 100

set CurDate=%mm%/%dd%/%yyyy%
set dayCnt=%1

if "%dayCnt%"=="" set dayCnt=1

REM Substract your days here
set /A dd=1%dd% - 100 - %dayCnt%
set /A mm=1%mm% - 100

:CHKDAY
if /I %dd% GTR 0 goto DONE
set /A mm=%mm% - 1
if /I %mm% GTR 0 goto ADJUSTDAY
set /A mm=12
set /A yyyy=%yyyy% - 1

:ADJUSTDAY
if %mm%==1 goto SET31
if %mm%==2 goto LEAPCHK
if %mm%==3 goto SET31
if %mm%==4 goto SET30
if %mm%==5 goto SET31
if %mm%==6 goto SET30
if %mm%==7 goto SET31
if %mm%==8 goto SET31
if %mm%==9 goto SET30
if %mm%==10 goto SET31
if %mm%==11 goto SET30
REM ** Month 12 falls through

:SET31
set /A dd=31 + %dd%
goto CHKDAY

:SET30
set /A dd=30 + %dd%
goto CHKDAY

:LEAPCHK
set /A tt=%yyyy% %% 4
if not %tt%==0 goto SET28
set /A tt=%yyyy% %% 100
if not %tt%==0 goto SET29
set /A tt=%yyyy% %% 400
if %tt%==0 goto SET29

:SET28
set /A dd=28 + %dd%
goto CHKDAY

:SET29
set /A dd=29 + %dd%
goto CHKDAY

:DONE
if /I %mm% LSS 10 set mm=0%mm%
if /I %dd% LSS 10 set dd=0%dd%

REM Set IIS and AWS date variables
set IISDT=%yyyy:~2,2%%mm%%dd%
set AWSDT=%yyyy%-%mm%-%dd%
于 2012-08-09T20:29:17.567 回答
3
@echo off
:: Strip the day of the week from the current date
FOR %%A IN (%Date%) DO SET Today=%%A
:: Parse the date, prefix day and month with an extra leading zero
FOR /F "tokens=1-3 delims=/" %%A IN ("%Today%") DO (
    SET Day=0%%A
    SET Month=0%%B
    SET Year=%%C
)
:: Remove excess leading zeroes
SET Day=%Day:~-2%
SET Month=%Month:~-2%
:: Display the results
SET Day
SET Month
SET Year
:: Convert to Julian date
CALL :JDate %Year% %Month% %Day%
:: Display the result
SET JDate
:: Subtract 1 day
SET /A JPast = JDate - 1
:: Display the result
SET JPast
:: Convert back to "normal" date again
CALL :GDate %JPast%
:: Display the result
::SET GDate=20130121
SET GDate

echo The previous day in form YYYYMMDD is %GDate%

pause
::::::::::::::::::::::::::::::::::::::::::::::::::::::

GOTO:EOF

:JDate
:: Convert date to Julian
:: Arguments : YYYY MM DD
:: Returns   : Julian date
::
:: First strip leading zeroes
SET MM=%2
SET DD=%3
IF %MM:~0,1% EQU 0 SET MM=%MM:~1%
IF %DD:~0,1% EQU 0 SET DD=%DD:~1%
::
:: Algorithm based on Fliegel-Van Flandern
:: algorithm from the Astronomical Almanac,
:: provided by Doctor Fenton on the Math Forum
:: (http://mathforum.org/library/drmath/view/51907.html),
:: and converted to batch code by Ron Bakowski.
SET /A Month1 = ( %MM% - 14 ) / 12
SET /A Year1  = %1 + 4800
SET /A JDate  = 1461 * ( %Year1% + %Month1% ) / 4 + 367 * ( %MM% - 2 -12 * %      Month1% ) / 12 - ( 3 * ( ( %Year1% + %Month1% + 100 ) / 100 ) ) / 4 + %DD% - 32075

SET Month1=
SET Year1=
GOTO:EOF
:GDate
:: Convert Julian date back to "normal" Gregorian date
:: Argument : Julian date  
:: Returns  : YYYY MM DD
:: 
:: Algorithm based on Fliegel-Van Flandern
:: algorithm from the Astronomical Almanac,
:: provided by Doctor Fenton on the Math Forum
:: (http://mathforum.org/library/drmath/view/51907.html),
:: and converted to batch code by Ron Bakowski.
::
SET /A P      = %1 + 68569
SET /A Q      = 4 * %P% / 146097
SET /A R      = %P% - ( 146097 * %Q% +3 ) / 4
SET /A S      = 4000 * ( %R% + 1 ) / 1461001
SET /A T      = %R% - 1461 * %S% / 4 + 31
SET /A U      = 80 * %T% / 2447
SET /A V      = %U% / 11
SET /A GYear  = 100 * ( %Q% - 49 ) + %S% + %V%
SET /A GMonth = %U% + 2 - 12 * %V%
SET /A GDay   = %T% - 2447 * %U% / 80
:: Clean up the mess
FOR %%A IN (P Q R S T U V) DO SET %%A=
:: Add leading zeroes
IF 1%GMonth% LSS 20 SET GMonth=0%GMonth%
IF 1%GDay%   LSS 20 SET GDay=0%GDay%
:: Return value
:: Here you can define the form that you want
SET GDate=%GYear%%GMonth%%GDay%
GOTO:EOF
于 2013-01-22T13:12:00.200 回答
2

这是一个即时创建 earlyday.vbs 文件、使用它并随后将其删除的解决方案。

它将结果存储在 NewDate 变量中

此示例计算 1 天前,但可以通过更改 Offset 变量的值轻松计算更早的日期。

@echo off
set Offset=1

echo d = date() - WScript.Arguments.Item(0) > earlierday.vbs
echo wscript.echo year(d) * 10000 + month(d) * 100 + day(d) >> earlierday.vbs

for /f %%a in ('cscript //nologo earlierday.vbs %Offset%') do set NewDate=%%a

del earlierday.vbs    
echo %NewDate%
pause

您可以通过使用 %temp%\earlierday.vbs 在用户的临时文件夹中创建文件来稍微改进这一点。

感谢paxdiablo,因为这是对他早期帖子的简单调整。

编辑:这里有一个循环,接近我真正需要它做的事情。这将在今天的日期休息 14 天并返回该日期。然后它将一次返回 7 天,直到返回 35 天前。

@echo off
SETLOCAL EnableDelayedExpansion

set BackDaysFrom=14
Set BackDaysTo=35
Set BackDaysStep=7

echo d = date() - WScript.Arguments.Item(0) > earlierday.vbs
echo wscript.echo year(d) * 10000 + month(d) * 100 + day(d) >> earlierday.vbs

for /L %%i in (%BackDaysFrom%, %BackDaysStep%, %BackDaysTo%) do (
    for /f %%a in ('cscript //nologo earlierday.vbs %%i') do set NewDate=%%a
    echo !NewDate!
)

del earlierday.vbs    

pause
于 2016-04-11T07:12:32.133 回答