mysql - MySql 访问冲突或语法错误

Question

当我尝试执行它下面的 sql 语句时，我收到以下错误。

SQLSTATE[42000]: Syntax error or access violation: 1064 You have an error in your SQL   syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'like, agree, favor, discriminator) VALUES ('5023fb89189df', 0, '2012-08-09 14:03' at line 1

完整的sql语句如下

INSERT INTO activity (id, hide_author, created, updated, access, location, disabled, created_ip, updated_ip, params, body, audit, hide_activity, author, owning_activity, like, agree, favor, discriminator) VALUES ('5023fa5a63d1b', NULL, '2012-08-09 13:58:50', '2012-08-09 13:58:50', NULL, NULL, 0, '192.168.1.1', NULL, NULL, 'Exactly, I would prefer to be able to defend myself when the unthinkable happens', NULL, 0, '50143c83e3f5a', '5023e63dafe18', 1, NULL, NULL, 'commentpost')

我没有看到语法有任何错误，但也许你们可以就可能导致哪种访问冲突提出一些建议。我应该寻找什么？

Answer 1

“Like”是 SQL 中的保留字。用反引号括起来。这是计算机上“1”旁边的键，如下所示：

INSERT INTO activity (id, hide_author, created, updated, access, location, disabled, created_ip, updated_ip, params, body, audit, hide_activity, author, owning_activity, `like`, agree, favor, discriminator) VALUES ('5023fa5a63d1b', NULL, '2012-08-09 13:58:50', '2012-08-09 13:58:50', NULL, NULL, 0, '192.168.1.1', NULL, NULL, 'Exactly, I would prefer to be able to defend myself when the unthinkable happens', NULL, 0, '50143c83e3f5a', '5023e63dafe18', 1, NULL, NULL, 'commentpost')