1

我试图找出两件事。

  1. 我可以优化我的代码以使其运行得更快吗
  2. 有没有办法测试我的脚本的速度。

我的脚本只是从 URL 中提取数据（例如：https ://www.sciencebase.gov/catalog/items?q=Water&max=100&format=json ），这些数据将粘贴到电子表格的第一个单元格中。然后它使用第一列存储标题和第二列存储摘要来填充单元格。

我正在使用将执行脚本 onEdit() 的触发器，以便在对电子表格的第一个单元格进行编辑时运行它。

任何指针，提示，甚至是去看看这里都表示赞赏

这是我的代码，

function respondToSearch() {

     // Gets the active sheet in a spreadsheet
     var ss = SpreadsheetApp.getActiveSpreadsheet(); 

     // Gets sheet 1 and sets the first column to a width of 200 and the second 
     column to width 500
     var sheet = ss.getSheets()[0].setColumnWidth(1, 200).setColumnWidth(2, 500);
     var activeSheet = SpreadsheetApp.getActiveSheet();

     // Gets the value from the top left cell in a range
     var dataRange = activeSheet.getDataRange().getValue();

     // Sends an HTTP request to fetch the URL
     var searchResponse = UrlFetchApp.fetch(dataRange);

     // Get the response as a string and parse (string is in JSON format) 
     var parsedResponse = Utilities.jsonParse(searchResponse.getContentText());

     // Array to hold letter corresponding to spreadsheet columns
     var cellLetters = ["a", "b", "c", "d", "e", "f", "g", "h", "i", "j", "k", "l", 
     "m", "n", "o", "p", "q", "r", "s", "t"];

     // Loop through the "item" objects and display the properties in the 
     spreadsheet
     for (var i = 0; i < 2; i++) {  
       for (var j = 0; j < parsedResponse.items.length; j++) {      

       // Starts with items[0] (1st object) and displays the properties
       var parsedItems = [parsedResponse.items[j].title, parsedResponse.items[j]
       .summary];

       // If a property is not undefined print the property in the spreadsheet 
       else print "N/A"
       if (parsedItems[i] != undefined) {
         var print = parsedItems[i];
       }
       else {
         var print = "N/A";
       }

       // Stores the current letter corresponding to the current spreadsheet column
       var cellLtr = cellLetters[i];

       // Starts the row available to display data at number 2
       var cellNum = [j + 2];
       var cell = cellLtr + cellNum;

       sheet.setActiveCell(cell).setFontSize("9").setHorizontalAlignment("left")
       .setVerticalAlignment("top").setValue(print);
      }
     }
    }

谢谢

4

2 回答 2

1

我可以优化我的代码以使其运行得更快吗

我认为这是可能的。尝试重写代码以设置字体大小和对齐方式，而不是为每个单元格而是为整个范围。

有没有办法测试我的脚本的速度。

是的。代码应如下所示

var start = new Date();
my_time_consuming_function();
var diff = new Date() - start;
Logger.log("my_time_consuming_function takes: " + diff + " ms");
于 2012-08-09T18:10:20.750 回答
0

您可以避免parsedItems[i]在cellLtr.j

for (var i = 0; i < 2; i++) {
    var cellLtr = cellLetters[i];
    for (var j = 0; j < parsedResponse.items.length; j++) {
        var print = (i == 0 ? parsedResponse.items[j].title : parsedResponse.items[j].summary);
        if (print == undefined)
            print = "N/A";

        var cell = cellLtr + (j + 2);

        sheet.setActiveCell(cell).setFontSize("9").setHorizontalAlignment("left")
            .setVerticalAlignment("top").setValue(print);
    }
}
于 2012-08-09T18:50:38.887 回答