oracle - Oracle PL/SQL 中是否有用于拆分文件和父目录的库函数？

Question

给定一个文件路径，我试图在 Oracle PL/SQL 中分隔文件名和父目录。我想知道 PL/SQL 库中是否已经有可用的函数

Answer 1

没有真正的需要，如果您使用的是 10g 或更高版本，它只需要一些正则表达式技巧，这取决于您的操作系统，可能如下所示：

with filepaths as (
  select '/home/oracle/somedir/blah.sql' as linux
       , 'c:\home\oracle\somedir\blah.sql' as windows
    from dual
         )
select regexp_substr(linux, '[^/]+', 1
                     , regexp_count(linux,'/')) as linux
     , regexp_substr(windows, '[^\]+', 1
                     , regexp_count(windows,'[^\]+')) as windows
  from filepaths
       ;

LINUX    WINDOWS
-------- --------
blah.sql blah.sql

Answer 2

INSTR 和 SUBSTR 字符串函数可用于执行此操作，如下所示：

WITH filepaths AS
  (SELECT '/home/oracle/somedir/blah.sql' AS LINUX,
          'c:\home\oracle\somedir\blah.sql' AS WINDOWS
     FROM DUAL)
SELECT LINUX,
       SUBSTR(LINUX, 1, INSTR(LINUX, '/', -1)) AS LINUX_PATH,
       SUBSTR(LINUX, INSTR(LINUX, '/', -1)+1) AS LINUX_FILE,
       WINDOWS,
       SUBSTR(WINDOWS, 1, INSTR(WINDOWS, '\', -1)) AS WINDOWS_PATH,
       SUBSTR(WINDOWS, INSTR(WINDOWS, '\', -1)+1) AS WINDOWS_FILE
FROM filepaths;

LINUX         /home/oracle/somedir/blah.sql
LINUX_PATH    /home/oracle/somedir/
LINUX_FILE    blah.sql
WINDOWS       c:\home\oracle\somedir\blah.sql
WINDOWS_PATH  c:\home\oracle\somedir\
WINDOWS_FILE  blah.sql

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