python - 使用 arcpy 编写 XML（Arcview 许可）

Question

我需要生成要素属性数据的 xml，但我只有 Arcview 许可证，所以不能使用导出 XML 工具。我有哪些选择？

谢谢

Answer 1

Python 的标准库中已经包含了你需要的一切。下面是在 shapefile 要素类上打开搜索光标并将选定字段及其值转储到 xml 元素的代码。当所有行都完成后，它将顶部的聚合元素转储到 xml 文件中。请注意，我使用的是仅在 10.1 中可用的 arcpy.da 搜索游标，但您可以轻松修改代码以使用常规 arcpy 搜索游标（或更新游标）。

#in some cases cElementTree won't be available, but it's lots faster,
#so get it if we can
try:
    import xml.etree.cElementTree as et
except ImportError:
    import xml.etree.ElementTree as et

import arcpy

def rows_as_dicts(cursor):
    '''
    Yields rows from passed Arcpy da cursor as dicts
    '''
    colnames = cursor.fields
    uc = hasattr(cursor, 'updateRow')
    for row in cursor:
        row_object = dict(zip(colnames, row))
        yield row_object
        if uc:
            cursor.updateRow([row_object[colname] for colname in colnames])

def dump2xml(row, stands, elelst):
    '''
    Builds the xml tree from the passed row dict
    '''

    # stand level creation
    stand = et.Element("stand")

    stand.set("tractid", row['TRACTID'])
    stand.set('stand', str(row['STAND']))

    # add field elements with their values
    for e in elelst:
        xele = et.SubElement(stand, e)
        xele.text = str(row[e])

    #add to top level stands element
    stands.append(stand)

def main():
    #establish top level element
    stands = et.Element("stands")

    #set fields to output to xml
    fields = ('MAPNAME ACRES TYP PROGRAM SI AGE YR').split()

    #get cursor going and make the xml elements
    fc = 'c:/arcview/sf/summerville/stand.shp'
    with arcpy.da.SearchCursor(fc, ['*']) as sc:
        for row in rows_as_dicts(sc):
            dump2xml(row, stands, fields)

    #throw the entire xml tree to a file        
    xmltree = et.ElementTree(stands)
    xmltree.write('c:/temp/stands.xml', encoding='UTF-8')

    return

if __name__ == '__main__':
    main()

祝你好运，

麦克风