JAVASCRIPT
function ShowContent(id) {
if(id.length < 1) { return; }
document.getElementById(id).style.display = "block";
}
PHP
$test = mysql_query('SELECT userid,testid,testname FROM test_table WHERE userid = 9 ORDER BY name');
TestName : <select>
while($row=mysql_fetch_array($test))
{
$testname = $row['testname'];
$testid = $row['testid'];
echo '<option value='.$testid.'>'.$testname.'</option>
}
</select>
echo '<div id="testid" style="display:none;">
echo '<table>
<tr><th>USERID</th</tr>
<tr><th>TESTNAME</th></tr>
<tr><th>MARKS</th></tr>
publishtest = mysql_query('SELECT id,userid,publishtest,marks FROM publish_table WHERE userid= 9 GROUP BY id');
while($row=mysql_fetch_array($publishtest))
{
$userid = $row['userid'];
$testid = $row['id']; /*This is test id*/
$testname = $row['publishtest']; /* This is test name*/
$marks = $row['marks'];
echo '<tr><td>'.$userid.'</td>
<td>'.testid.'</td>
<td>'.testname.'</td>
<td>'.$marks.'</td>
</tr>
}
echo '</table>';
echo '</div>';
当我从选择标签中选择测试时,我需要显示该 testid 的 div。我想要javascript,jquery