我正在尝试删除常规文本周围的单引号。例如，给定列表：
alist = ["'ABC'", '(-inf-0.5]', '(4800-20800]', "'\\'(4.5-inf)\\''", "'\\'(2.75-3.25]\\''"]
我想将“'ABC'”变成“ABC”，但保留其他引号，即：
alist = ["ABC", '(-inf-0.5]', '(4800-20800]', "'\\'(4.5-inf)\\''", "'\\'(2.75-3.25]\\''"]
我尝试使用如下外观：
fixRepeatedQuotes = lambda text: re.sub(r'(?<!\\\'?)\'(?!\\)', r'', text)
print [fixRepeatedQuotes(str) for str in alist]
但收到错误消息：
sre_constants.error: look-behind requires fixed-width pattern.
还有其他解决方法吗？提前非常感谢！
尝试应该工作：
result = re.sub("""(?s)(?:')([^'"]+)(?:')""", r"\1", subject)
解释
"""
(?: # Match the regular expression below
' # Match the character “'” literally (but the ? makes it a non-capturing group)
)
( # Match the regular expression below and capture its match into backreference number 1
[^'"] # Match a single character NOT present in the list “'"” from this character class (aka any character matches except a single and double quote)
+ # Between one and unlimited times, as many times as possible, giving back as needed (greedy)
)
(?: # Match the regular expression below
' # Match the character “'” literally (but the ? makes it a non-capturing group)
)
"""
re.sub接受一个函数作为替换文本。所以，
re.sub(r"'([A-Za-z]+)'", lambda match: match.group(), "'ABC'")
产量
"ABC"