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我的目标是创建具有无限深度树的导航菜单。我可以成功生成前 2 个级别。第一个(顶级)使用未存储在 XML 文件中的 PHP 数组。第二个是从一个平面 xml 文件生成的。主要问题是成功的递归。

这是 XML 结构:

<articles>
    <article>
        <menu parent="Insurance" label="Business" target="#" show="true" />
        <data />
        <body />
    </article>
    <article>
        <menu parent="Resources" label="Videos" target="content.php#videos" show="true" />
        <data />
        <body />
    </article>
    <article>
        <menu parent="Business" label="Disability" target="content.php#disability" show="true" />
        <data />
        <body />
    </article>
    <article>
        <menu parent="Business" label="Liability" target="content.php#liability" show="true" />
        <data />
        <body />
    </article>

</articles>

我在目标属性中使用 # 来确定是否需要启动新列表(子菜单)。

我收到的输出正确信息成功的 PHP 代码是:

    $objXMLMenu = simplexml_load_file('menu.xml');
    foreach ($mainmenu as $menuparent) {  //Main Array

        echo "<li><a href=\"" .$maintargets[$i]. "\">". $menuparent ."</a>\n";  // Top Menu array. I use 2 for clarity
        if ($maintargets[$i] == "#"){


            //Open the ULs for filling
            echo "\t<ul>\n";

    // Start function here?

            foreach($objXMLMenu->article as $art){

                foreach($art->menu as $menuitem){

                    if($menuitem['parent'] == $menuparent){ //Compare to Main Array

                        if ($menuitem['show'] == "true"){

                            if($menuitem['target'] == "#"){  //A Submenu exits here
                                echo "\t\t<li><a href=\"" . $menuitem['target'] . "\" >" .$menuitem['label'] . "</a></li>\n";
                                echo "\t\t\t<ul>\n";
                                //Run XMLQUERY match? As a 

                                echo "\t\t\t</ul>\n";
                            }else{
                                echo "\t\t<li><a href=\"" . $menuitem['target'] . " \"rel=\"ajax\">" .$menuitem['label'] . "</a></li>\n";
                            }
                        }

                    }
                }

            }
            //Close Middle Menus
            echo "\t</ul>";
        }
        $i++;
        //close Top Level Menu Item
        echo "</li>\n";
    }
//<UL> Footer
echo "\t</ul>\n</div>\n";

为了使其成为递归函数,我的第一个 foreach 语句收到错误,这表明我应该切换到 DOM 和 XPATH 而不是 simplexml。这是我到目前为止提出的功能:

$objXMLMenu = simplexml_load_file('menu.xml');
// Start function here!
function mysubmenu($menuparent){
    foreach($objXMLMenu->article as $art){
        foreach($art->menu as $menuitem){
            if($menuitem['label'] == $menuparent){
            //Compare to Main Array
                if ($menuitem['show'] == "true"){

                    if($menuitem['target'] == "#"){
                        // ((ROOT)
                        //A Submenu exits here
                        $strResponse .= "\t\t<li><a href=\"" . $menuitem['target'] . " \">" .$menuitem['label'] . "</a></li>\n";
                        $strResponse .= "\t\t\t<ul>\n";

                        //xmlpath QUERY instead?
                        mysubmenu($menuitem['parent']);

                        $strResponse .= "\t\t\t</ul>\n";
                    }else{
                        $strResponse .= "\t\t<li><a href=\"" . $menuitem['target'] . " \"rel=\"ajax\">" .$menuitem['label'] . "</a></li>\n";
                    }
                }

            }
        }
        //insert counter to stop foreach loop after all records are posted.
    }
    return $strResponse; 
} //End Function

这种类型的递归对我来说是一个新的界限。我发现的每个示例或解释都涉及到 XML 树对元素的深入研究。“深度”(计数器)属性不是一个选项。因为,随着时间的推移,我在一个真正无限深度的“推迟”项目中面临着类似的问题。

4

1 回答 1

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对程序风格起作用的东西在功能中不起作用。我最麻烦的方面是比较 SimpleXML 对象。大约有 5 行需要更改。尽管对于更长的递归,可能有一种更简单、更快的方法来获得这个答案。但我发现这暂时有效。

function mysubmenu($menuparent){
    $objXMLMenu = simplexml_load_file('menu.xml');
    foreach($objXMLMenu->article as $art){
        foreach($art->menu as $menuitem){

            if((string)$menuitem['parent'] == $menuparent){ 
                if ($menuitem['show'] == "true"){
                    if($menuitem['target'] == "#"){
                        echo "\t\t<li><a href=\"" . $menuitem['target'] . "\">" .$menuitem['label'] . "</a></li>\n";
                        echo "\t\t\t<ul>\n";
                        mysubmenu($menuitem['label']);
                        echo "\t\t\t</ul>\n";
                    }else{
                        echo "\t\t<li><a href=\"" . $menuitem['target'] . "\" rel=\"ajax\">" .$menuitem['label'] . "</a></li>\n";
                    }
                }


            }
        }

    }

} //End Function 
于 2012-08-09T13:48:05.920 回答