php - 使用 while 以正确的顺序在表中打印 sql 计数结果

Question

我有 2 个while循环，一个在另一个循环中。

所以

while ($info5 = mysql_fetch_array($result5))
{

 print "</td>";

然后我有这个 sql 查询

 include('database.inc');

$sql6 = "SELECT count(checkins.placeID) as methoda FROM checkins, places, activities WHERE activities.actID=places.placeActivity AND checkins.placeID = places.placeID and checkins.cityID = ".$city." group by checkins.placeID order by checkins.placeID, activityName";

$result6=mysql_query($sql6);
$count=mysql_num_rows($result6);

while($row = mysql_fetch_array($result6))
    {
     echo $row["methoda"];
 }
      print "</td></tr></table>" ;

        }?>

问题是我收到 1 个表，例如：

Place1 -> 321

Place2 -> 321

Place3 -> 321

顺序是正确的，但我将它作为数组接收！正确的应该是

Place1 -> 3

Place2 -> 2

Place3 -> 1

我不知道如何拆分数组$row，或者是转置问题，还是count命令已经堆叠等等。我真的不知道！请帮我。

Answer 1

代码应该是这样的：

include('database.inc');

echo "<table>";

//first query....

while ($info5 = mysql_fetch_array($result5))
{

    $sql6 = "SELECT count(checkins.placeID) as methoda FROM checkins, places, activities WHERE activities.actID=places.placeActivity AND checkins.placeID = places.placeID and checkins.cityID = ".$city." group by checkins.placeID order by checkins.placeID, activityName";

    $result6=mysql_query($sql6);
    $count=mysql_num_rows($result6);

    echo "<tr>";
    while($row = mysql_fetch_array($result6))
    {
       echo "<td>".$row["methoda"]."</td>";
    }
    print "</tr>" ;

}?></table>

根据您的要求对其进行编辑。注意td,tr和table标签的位置