java - 删除特殊字符前后的空格

Question

我有一个字符串，

String sample = "He won the International Rating Chess Tournament (IRCT ) which concluded on Dec. 22 at the Blue Sky Hotel , Canada";

我想删除字符')'和','之前留下的空格（如果有的话）。所以最终的输出应该是这样的，

He won the International Rating Chess Tournament (IRCT) which concluded on Dec. 22 at the Blue Sky Hotel, Canada

谁能告诉我该怎么做？

Answer 1

sample.replaceAll("\\s+(?=[),])", "");

即删除所有\s+紧随其后的(?=...)任何字符的空格[),]。双反斜杠用于转义。有关正则表达式的更多信息可以在这里看到：

http://docs.oracle.com/javase/7/docs/api/java/util/regex/Pattern.html

Answer 2

sample = sample.replaceAll(" ,", ",").replaceAll(" )", ")");

如果要在)and之前删除任意数量的空格,，可以使用正则表达式：

sample = sample.replaceAll("\\s+,", ",").replaceAll("\\s+\\)", ")");

Answer 3

    String sample = "He won the International Rating Chess Tournament (IRCT ) which concluded on Dec. 22 at the Blue Sky Hotel , Canada";
    sample=sample.replace(" )", ")");
    sample=sample.replace(" ,", ",");

Answer 4

此正则表达式应删除前后的空格 -

\s+(?=[-])|(?<=-)\s*