4

只想检查这个带有异步任务的 JSON Parser 是否正确完成？当我将此代码放入我的 Eclipse 时，此 (method.equals("POST") 带有红色下划线。它指出“方法”无法解决。对此有任何建议或帮助吗？谢谢。

public class JSONParser {

  static InputStream is = null;
  static JSONObject jObj = null;
  static String json = "";
  String url=null;
     List<NameValuePair> nvp=null;
     // constructor
     public JSONParser() {

   }

  // function get json from url
  // by making HTTP POST or GET method
   public JSONObject makeHttpRequest(String url, String method,
        List<NameValuePair> params) {
      BackGroundTask Task= new BackGroundTask(url, method,  params);
    try {
        return Task.execute().get();
    } catch (InterruptedException e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
        return null;
    } catch (ExecutionException e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
        return null;
    }
}
public class BackGroundTask extends AsyncTask<String, String, JSONObject>{
    List<NameValuePair> postparams= new ArrayList<NameValuePair>();
    String URL=null;
public BackGroundTask(String url, String method, List<NameValuePair> params) {
        URL=url;
        postparams=params;
    }
    @Override
    protected JSONObject doInBackground(String... params) {
        // TODO Auto-generated method stub
        // Making HTTP request
        try {
    // Making HTTP request 
        // check for request method

    if(method.equals("POST")){
            // request method is POST
            // defaultHttpClient
            DefaultHttpClient httpClient = new DefaultHttpClient();
            HttpPost httpPost = new HttpPost(url);
            httpPost.setEntity(new UrlEncodedFormEntity(postparams));

            HttpResponse httpResponse = httpClient.execute(httpPost);
            HttpEntity httpEntity = httpResponse.getEntity();
            is = httpEntity.getContent();

        }else if(method == "GET"){
            // request method is GET
            DefaultHttpClient httpClient = new DefaultHttpClient();
            String paramString = URLEncodedUtils.format(postparams, "utf-8");
            url += "?" + paramString;
            HttpGet httpGet = new HttpGet(url);

            HttpResponse httpResponse = httpClient.execute(httpGet);
            HttpEntity httpEntity = httpResponse.getEntity();
            is = httpEntity.getContent();
        }           

    } catch (UnsupportedEncodingException e) {
        e.printStackTrace();
    } catch (ClientProtocolException e) {
        e.printStackTrace();
    } catch (IOException e) {
        e.printStackTrace();
    }

    try {

        BufferedReader reader = new BufferedReader(new InputStreamReader(
                is, "iso-8859-1"), 8);
        StringBuilder sb = new StringBuilder();
        String line = null;
        while ((line = reader.readLine()) != null) {
            sb.append(line + "\n");
        }
        is.close();
        json = sb.toString();
    } catch (Exception e) {
        Log.e("Buffer Error", "Error converting result " + e.toString());
    }

    // try parse the string to a JSON object
    try {
        jObj = new JSONObject(json);
    } catch (JSONException e) {
        Log.e("JSON Parser", "Error parsing data " + e.toString());
    }

    // return JSON String
    return jObj;

   }
 }
}
4

2 回答 2

12

您忘记method在 BackGroundTask 类中声明属性。

编辑像这样：

public class BackGroundTask extends AsyncTask<String, String, JSONObject>{
    List<NameValuePair> postparams= new ArrayList<NameValuePair>();
    String URL=null;
    String method = null;
public BackGroundTask(String url, String method, List<NameValuePair> params) {
        URL=url;
        postparams=params;
        this.method = method;
    }
    @Override
    protected JSONObject doInBackground(String... params) {
        // TODO Auto-generated method stub
        // Making HTTP request
        try {
    // Making HTTP request 
        // check for request method

    if(method.equals("POST")){
            // request method is POST
            // defaultHttpClient
            DefaultHttpClient httpClient = new DefaultHttpClient();
            HttpPost httpPost = new HttpPost(url);
            httpPost.setEntity(new UrlEncodedFormEntity(postparams));

            HttpResponse httpResponse = httpClient.execute(httpPost);
            HttpEntity httpEntity = httpResponse.getEntity();
            is = httpEntity.getContent();

        }else if(method == "GET"){
            // request method is GET
            DefaultHttpClient httpClient = new DefaultHttpClient();
            String paramString = URLEncodedUtils.format(postparams, "utf-8");
            url += "?" + paramString;
            HttpGet httpGet = new HttpGet(url);

            HttpResponse httpResponse = httpClient.execute(httpGet);
            HttpEntity httpEntity = httpResponse.getEntity();
            is = httpEntity.getContent();
        }           

    } catch (UnsupportedEncodingException e) {
        e.printStackTrace();
    } catch (ClientProtocolException e) {
        e.printStackTrace();
    } catch (IOException e) {
        e.printStackTrace();
    }

    try {

        BufferedReader reader = new BufferedReader(new InputStreamReader(
                is, "iso-8859-1"), 8);
        StringBuilder sb = new StringBuilder();
        String line = null;
        while ((line = reader.readLine()) != null) {
            sb.append(line + "\n");
        }
        is.close();
        json = sb.toString();
    } catch (Exception e) {
        Log.e("Buffer Error", "Error converting result " + e.toString());
    }

    // try parse the string to a JSON object
    try {
        jObj = new JSONObject(json);
    } catch (JSONException e) {
        Log.e("JSON Parser", "Error parsing data " + e.toString());
    }

    // return JSON String
    return jObj;

   }
 }
}
于 2012-08-08T13:37:10.833 回答
1

您需要在 BackGroundTask 中将方法设置为类变量。您正在将它传递给构造函数，但不会对其进行任何处理。使用与 url 和 postparams 相同的方式设置它。

于 2012-08-08T13:35:21.180 回答