我必须从 TabActivity 的 5 个片段中修改几个布局的后退按钮命令。我为主要活动尝试了这段代码:
@Override
public void onTabChanged(String tabId) {
TabInfo newTab = mTabs.get(tabId);
if(mTabHost.getCurrentTab() == 0){
backpag=0;
}
if (mTabHost.getCurrentTab() == 1) {
backpag=1;
}
if (mTabHost.getCurrentTab() == 2) {
backpag=2;
}
if (mTabHost.getCurrentTab() == 3) {
backpag=3;
}
if (mTabHost.getCurrentTab() == 4) {
backpag=4;
}
if (mTabHost.getCurrentTab() == 5) {
backpag=5;
}
if (mLastTab != newTab) {
FragmentTransaction ft = mActivity.getSupportFragmentManager().beginTransaction();
if (mLastTab != null) {
if (mLastTab.fragment != null) {
ft.detach(mLastTab.fragment);
}
}
if (newTab != null) {
if (newTab.fragment == null) {
newTab.fragment = Fragment.instantiate(mActivity, newTab.clss.getName(), newTab.args);
ft.add(mContainerId, newTab.fragment, newTab.tag);
} else {
ft.attach(newTab.fragment);
}
}
mLastTab = newTab;
ft.commit();
mActivity.getSupportFragmentManager().executePendingTransactions();
}
}
}
@Override
public void onBackPressed() {
System.out.println("mtabhost" + mTabHost.getCurrentTab());
if (backpag == 1) {
VinocardFragment.onBackPressed();
} else if (backpag == 2) {
StandorteFragment.getInstance().onBackPressedStandorte();
} else if (backpag == 3) {
// StandorteFragment.onBackPressed();
} else if (backpag == 4) {
// StandorteFragment.onBackPressed();
} else if (backpag == 5) {
SonstigesFragment.onBackPressed();
} else if (backpag == 0) {
System.out.println("inainte d getinstance");
LoggedFragment.getInstance().onBackPressedLogged();
backpag=-1;
System.out.println("mtabhost" + backpag);
} else if(backpag==-1) {
System.out.println("mtabhost" + backpag);
finish();
}
}
但是当我到达第一个选项卡(backpag = 0)时,我按下后退按钮并开始一个循环,就像我只需按下后退按钮一样,它会转到第一个选项卡和它之前的选项卡。在我的逻辑中,我按下后退按钮形成它应该退出的第一个选项卡(完成())。任何想法为什么会发生这种情况?