我公司的部署过程要求用于创建过程和表等的 SQL 脚本是裸露的。
在 SQL Server Management Studio 中生成创建脚本给您带来的不仅仅是一个裸脚本，这在这种情况下是不幸的。例如，对于一个测试表，这是 SSMS 为我生成的：
USE [DemoDB]
GO
/****** Object: Table [dbo].[example] Script Date: 08/07/2012 15:46:32 ******/
SET ANSI_NULLS ON
GO
SET QUOTED_IDENTIFIER ON
GO
CREATE TABLE [dbo].[example](
[fake_row] [int] NULL
) ON [PRIMARY]
GO
所以，我想知道的是：
我可以在 SSMS 中以某种方式在 SQL Server 上运行一个查询，它会给我一个实际上只是以下内容的脚本吗？
create table example (
fake_row int
)
您可以使用 information_schema (Aaron ... 我知道，INFORMATION_SCHEMA ;) 创建自己的“创建表”语句。
我为此编写了一些代码，但它不使用 INFORMATION_SCHEMA。我知道，如果使用可能计划删除的旧系统表。它还添加了一些附加信息（您可以将其删除，因为您不需要它）。只需将表列表放在@INCLUSIONLIST 中，然后在表所在的数据库中运行它。
SET @INCLUSIONLIST = '|table1|table2|';
SELECT (CASE WHEN rownum = 1 THEN 'CREATE TABLE ['+a.t_name+'] ('
WHEN c.column_id IS NOT NULL
THEN ' ['+c.c_name+'] ' +
(CASE WHEN CHARINDEX('CHAR', datatype) > 0 THEN datatype+'('+(case when length < 0 then 'max' else cast(length as varchar) end)+')'
WHEN CHARINDEX('BINARY', datatype) > 0 THEN datatype+'('+cast(length as varchar)+')'
WHEN datatype = 'float' AND precision <> 24 THEN datatype+'('+cast(precision as varchar)+')'
WHEN datatype IN ('numeric', 'decimal') AND scale = 0 THEN datatype+'('+cast(precision as varchar)+')'
WHEN datatype IN ('numeric', 'decimal') AND scale > 0 THEN datatype+'('+cast(precision as varchar)+','+cast(scale as varchar)+')'
ELSE datatype END)+' '+
(CASE WHEN c.identity_seed IS NOT NULL
THEN 'IDENTITY(' + CAST(identity_seed AS VARCHAR) + ',' + CAST(identity_increment AS VARCHAR) + ') '
ELSE '' END) +
(CASE WHEN c.is_nullable = 0 THEN 'NOT NULL ' ELSE '' END) +
(CASE WHEN c.default_definition IS NOT NULL
THEN 'DEFAULT '+default_definition ELSE '' END) +
(CASE WHEN max_column_id = column_id AND pk.pk_name IS NULL THEN '' ELSE ',' END)
WHEN rownum = max_column_id + 2 and pk.pk_name IS NOT NULL
THEN ' PRIMARY KEY ('+pk.pk_columns+')'
WHEN rownum = max_column_id + 3 THEN ') /* CREATE TABLE '+a.t_name+' */'
WHEN rownum = max_column_id + 4 THEN 'GO'
WHEN rownum = max_column_id + 5 THEN ''
END)
FROM (SELECT t.t_name, rownum, max_column_id
FROM (SELECT t.name as t_name, MAX(c.column_id) as max_column_id
FROM sys.columns c join
(SELECT * FROM sys.tables WHERE CHARINDEX('|'+name+'|', @INCLUSIONLIST) > 0 ) t
ON c.object_id = t.object_id
GROUP BY t.name) t join
(SELECT ROW_NUMBER() OVER (ORDER BY object_id) as rownum FROM sys.columns c) ctr
ON ctr.rownum <= t.max_column_id + 5
) a LEFT OUTER JOIN
(SELECT t.name as t_name, c.column_id, c.name AS c_name, u.name as datatype,
ISNULL(baset.name, N'') AS systemtype,
CAST(CASE WHEN baset.name IN (N'nchar', N'nvarchar') AND c.max_length <> -1
THEN c.max_length/2 ELSE c.max_length END AS INT) AS length,
c.precision AS precision,
c.scale as scale,
c.is_nullable,
dc.definition as default_definition,
idc.seed_value as identity_seed, idc.increment_value as identity_increment
FROM sys.tables t JOIN
sys.all_columns AS c
ON c.object_id = t.object_id LEFT OUTER JOIN
sys.types u
ON u.user_type_id = c.user_type_id LEFT OUTER JOIN
sys.types baset
ON baset.user_type_id = c.system_type_id AND
baset.user_type_id = baset.system_type_id LEFT OUTER JOIN
sys.default_constraints dc
ON c.object_id = dc.parent_object_id AND
c.column_id = dc.parent_column_id LEFT OUTER JOIN
sys.identity_columns idc
ON c.object_id = idc.object_id AND
c.column_id = idc.column_id
) c
ON a.t_name = c.t_name AND
c.column_id + 1 = a.rownum LEFT OUTER JOIN
(SELECT t.name as t_name, kc.name as pk_name,
(MAX(CASE WHEN index_column_id = 1 THEN '['+c.name+']' ELSE '' END) +
MAX(CASE WHEN index_column_id = 2 THEN ','+'['+c.name+']' ELSE '' END) +
MAX(CASE WHEN index_column_id = 3 THEN ','+'['+c.name+']' ELSE '' END) +
MAX(CASE WHEN index_column_id = 4 THEN ','+'['+c.name+']' ELSE '' END) +
MAX(CASE WHEN index_column_id = 5 THEN ','+'['+c.name+']' ELSE '' END) +
MAX(CASE WHEN index_column_id = 6 THEN ','+'['+c.name+']' ELSE '' END) +
MAX(CASE WHEN index_column_id = 7 THEN ','+'['+c.name+']' ELSE '' END) +
MAX(CASE WHEN index_column_id = 8 THEN ','+'['+c.name+']' ELSE '' END) +
MAX(CASE WHEN index_column_id = 9 THEN ','+'['+c.name+']' ELSE '' END) +
MAX(CASE WHEN index_column_id = 10 THEN ','+'['+c.name+']' ELSE '' END)
) as pk_columns
FROM sys.indexes i JOIN
sys.key_constraints kc
ON i.name = kc.name AND
kc.type = 'PK' JOIN
sys.tables t
ON i.object_id = t.object_id JOIN
sys.index_columns ic
ON i.object_id = ic.object_id AND
i.index_id = ic.index_id JOIN
sys.columns c
ON ic.index_column_id = c.column_id AND
ic.object_id = c.object_id
GROUP BY t.name, kc.name
) pk
ON pk.t_name = a.t_name
ORDER BY a.t_name, rownum
为自我回答道歉，将其他好的答案标记为 +1。
事实证明，您可以通过 SSMS 中的实用程序获得几乎所有的方法。
或者，您可以控制 SSMS 的一般脚本行为，如下所示：脚本 SQL Server 数据库对象的选项。
我将创建从 INFORMATION_SCHEMA 视图读取的存储过程。获取存储的过程文本只是：
DECLARE @SQL VARCHAR(8000)
SET @SQL=' '
select @SQL = @SQL + ROUTINE_DEFINITION
from INFORMATION_SCHEMA.ROUTINES
where ROUTINE_TYPE='PROCEDURE'
AND SPECIFIC_NAME = 'updateComments'
PRINT @SQL
为表格编写脚本的脚本如下所示：
DECLARE @tableName VARCHAR(50)
SET @tableName = 'Location'
-- Need to know how many columns
DECLARE @NumColumns int
SELECT @NumColumns = MAX(ORDINAL_POSITION)
FROM INFORMATION_SCHEMA.COLUMNS
WHERE TABLE_NAME = @tableName
DECLARE @SQL VARCHAR(8000)
SET @SQL=' '
DECLARE @Results TABLE
(LineNumber int,
Line VARCHAR(1000))
INSERT INTO @Results
SELECT 0 AS ORDINAL_POSITION,
'CREATE TABLE '+TABLE_SCHEMA+'.'+@tableName+' (' AS Line
FROM INFORMATION_SCHEMA.TABLES
WHERE TABLE_NAME = @tableName
UNION ALL
SELECT ORDINAL_POSITION,
'['+COLUMN_NAME+'] '+ DATA_TYPE +
CASE WHEN DATA_TYPE = 'varchar' OR DATA_TYPE = 'char'
THEN '('+ CAST(CHARACTER_MAXIMUM_LENGTH AS VARCHAR) +')'
ELSE '' END +
CASE WHEN IS_NULLABLE = 'NO'
THEN ' NULL '
ELSE ' NOT NULL' END +
CASE WHEN ORDINAL_POSITION < @NumColumns
THEN ', '
ELSE ' ' END
AS LINE
FROM INFORMATION_SCHEMA.COLUMNS
WHERE TABLE_NAME = @tableName
UNION ALL
SELECT 999, ' )'
SELECT Line
FROM @Results
ORDER BY LineNumber
SELECT @SQL = @SQL + Line
FROM @Results
ORDER BY LineNumber
SELECT @SQL
PRINT @SQL
这将创建您想要的简单表格脚本，但它并不完整 - 不执行数字精度、主键等。但这足以让您入门。
我只是将其中的每一个都放入一个以对象名称作为参数的存储过程中。