5

对于这个非常菜鸟的问题，我很抱歉，但我对bash编程有点陌生（几天前开始）。基本上我想要做的是保留一个文件与另一个文件的所有单词出现

我知道我可以这样做：

sort | uniq -c | sort

问题是在那之后我想获取第二个文件，再次计算出现次数并更新第一个文件。之后我拿了第三个文件等等。

我现在正在做的事情没有任何问题（我正在使用grep,sed和awk），但它看起来很慢。

我很确定有一个非常有效的方法，只需要一个命令左右，使用uniq，但我不知道。

你能带我走正确的路吗？

我还粘贴了我写的代码：

#!/bin/bash
#   count the number of word occurrences from a file and writes to another file #
#   the words are listed from the most frequent to the less one                 #

touch .check                # used to check the occurrances. Temporary file
touch distribution.txt      # final file with all the occurrences calculated

page=$1             # contains the file I'm calculating
occurrences=$2          # temporary file for the occurrences

# takes all the words from the file $page and orders them by occurrences
cat $page | tr -cs A-Za-z\' '\n'| tr A-Z a-z > .check

# loop to update the old file with the new information
# basically what I do is check word by word and add them to the old file as an update
cat .check | while read words
do
    word=${words}       # word I'm calculating
    strlen=${#word}     # word's length
    # I use a black list to not calculate banned words (for example very small ones or inunfluent words, like articles and prepositions
    if ! grep -Fxq $word .blacklist && [ $strlen -gt 2 ]
    then
        # if the word was never found before it writes it with 1 occurrence
        if [ `egrep -c -i "^$word: " $occurrences` -eq 0 ]
        then
            echo "$word: 1" | cat >> $occurrences
        # else it calculates the occurrences
        else
            old=`awk -v words=$word -F": " '$1==words { print $2 }' $occurrences`
            let "new=old+1"
            sed -i "s/^$word: $old$/$word: $new/g" $occurrences
        fi
    fi
done

rm .check

# finally it orders the words
awk -F": " '{print $2" "$1}' $occurrences | sort -rn | awk -F" " '{print $2": "$1}' > distribution.txt
4

1 回答 1

8

好吧，我不确定我是否明白你想要做的事情的重点，但我会这样做：

while read file
do
  cat $file | tr -cs A-Za-z\' '\n'| tr A-Z a-z | sort | uniq -c > stat.$file
done < file-list

现在你有了所有文件的统计信息，现在你可以简单地聚合它：

while read file
do
  cat stat.$file
done < file-list \
| sort -k2 \
| awk '{if ($2!=prev) {print s" "prev; s=0;}s+=$1;prev=$2;}END{print s" "prev;}'

使用示例：

$ for i in ls bash cp; do man $i > $i.txt ; done
$ cat <<EOF > file-list
> ls.txt
> bash.txt
> cp.txt
> EOF

$ while read file; do
> cat $file | tr -cs A-Za-z\' '\n'| tr A-Z a-z | sort | uniq -c > stat.$file
> done < file-list

$ while read file
> do
>   cat stat.$file
> done < file-list \
> | sort -k2 \
> | awk '{if ($2!=prev) {print s" "prev; s=0;}s+=$1;prev=$2;}END{print s" "prev;}' | sort -rn | head

3875 the
1671 is
1137 to
1118 a
1072 of
793 if
744 and
533 command
514 in
507 shell
于 2012-08-07T17:59:51.430 回答