56

我希望在我的服务中添加一个操作过滤器，以处理将链接数据添加到响应消息中。我发现我需要模拟 HttpActionExecutedContext 但这是一个很难模拟的类，你如何处理动作过滤器测试？

4

6 回答 6

62

您可以创建一个假的HttpActionExecutedContext如下：

public static HttpActionContext CreateActionContext(HttpControllerContext controllerContext = null, HttpActionDescriptor actionDescriptor = null)
{
    HttpControllerContext context = controllerContext ?? ContextUtil.CreateControllerContext();
    HttpActionDescriptor descriptor = actionDescriptor ?? new Mock<HttpActionDescriptor>() { CallBase = true }.Object;
    return new HttpActionContext(context, descriptor);
}

public static HttpActionExecutedContext GetActionExecutedContext(HttpRequestMessage request, HttpResponseMessage response)
{
    HttpActionContext actionContext = CreateActionContext();
    actionContext.ControllerContext.Request = request;
    HttpActionExecutedContext actionExecutedContext = new HttpActionExecutedContext(actionContext, null) { Response = response };
    return actionExecutedContext;
}

我刚刚从 ASP.NET Web API 源代码中复制并粘贴了该代码：ContextUtil类。以下是一些关于他们如何测试一些内置过滤器的示例：

ActionFilterAttributeTest是测试类，ActionFilterAttribute它是一个抽象类，但你会明白的。

于 2012-08-07T18:15:01.787 回答
26

刚上新的。

private HttpActionContext CreateExecutingContext()
{
    return new HttpActionContext { ControllerContext = new HttpControllerContext {   Request = new HttpRequestMessage() } };
}

private HttpActionExecutedContext CreateExecutedContextWithStatusCode(HttpStatusCode statusCode)
{
    return new HttpActionExecutedContext
    {
        ActionContext = new HttpActionContext
        {
            ControllerContext = new HttpControllerContext
            {
                Request = new HttpRequestMessage()
            }
        },
        Response = new HttpResponseMessage
        {
            StatusCode = statusCode,
            Content = new StringContent("blah")
        }
    };
}
于 2014-12-17T14:30:52.143 回答
11

在尝试测试我构建的自定义未处理异常过滤器时，我遇到了同样的问题。

这成功了。大量的更新和很长的代码行。

var httpActionExecutedContext = new HttpActionExecutedContext(
    new HttpActionContext(
        new HttpControllerContext(
            new HttpConfiguration(),
            Substitute.For<IHttpRouteData>(),
            new HttpRequestMessage()),
    Substitute.For<HttpActionDescriptor>()),
    null);

使用了 NSubstiute，但您选择的任何处理抽象基类的模拟框架都可以。

希望这可以帮助

于 2013-07-11T16:16:02.880 回答
6

我也一直在用头撞砖墙。我尝试了 contextUtil但不断收到空引用异常。我在这篇文章中找到了如何调用 actionFilter NB 使用过滤器的 Mock 实例时没有调用 actionFilter，我必须使用真实对象。高温高压

具体来说：

var httpActionContext = new HttpActionContext
{
    ControllerContext = new HttpControllerContext
    {
        Request = requestMessage
    }
};

//call filter
var filter = new FooFilter();
filter.OnActionExecuting(httpActionContext);
于 2014-02-24T12:31:52.093 回答
5

参考https://stackoverflow.com/a/44447349/5547177

您可以使用以下内容自己创建 HTTPActionContext：

 _ctx = new HttpActionContext
        {
            ControllerContext = new HttpControllerContext()
            {
                Request = new HttpRequestMessage()

            }
        };
        _ctx.Request.Properties[System.Web.Http.Hosting.HttpPropertyKeys.HttpConfigurationKey] = new HttpConfiguration();

诀窍是没有 Request.Properties 条目设置，它将显示以下错误：

请求没有关联的配置对象或提供的配置为空。

这可能是设计者的疏忽，因为您可以在 HTTPActionContext 构造函数中设置 HTTPConfiguration！

于 2019-01-18T16:36:19.380 回答
3

这是 2018 年的一个工作示例（.NET Framework 4.5.1）。它使用 ExceptionFilterAttribute，但对于其他 FilterAttributes 应该是类似的。

[Test]
public void MyTest()
{
    var request = new HttpRequestMessage(HttpMethod.Get, new Uri("http://www.google.com"));
    var response = new HttpResponseMessage();

    // This next line is necessary to avoid the following error
    // if you call `context.Request.CreateResponse(...)` inside the filter:
    // System.InvalidOperationException: The request does not have an associated configuration object or the provided configuration was null.
    // Discovered from https://stackoverflow.com/a/44447355/3312114
    request.SetConfiguration(new HttpConfiguration());

    var context = ContextUtil.GetActionExecutedContext(request, response);

    _myFilter.OnException(context); // Execute your methods

    Assert.AreEqual(HttpStatusCode.InternalServerError, context.Response.StatusCode); // Make your assertions
}

然后只需将 ContextUtil 类复制到您的测试项目中的某个地方。@thomasb 对 @tugberk 的回答的评论表明最新的代码在 Codeplex 上。虽然该评论是在 2014 年，所以甚至可能会有以后的代码，但 2014 年的代码对我有用（2018 年 1 月），而原始链接代码却没有。为方便起见，我复制了下面的更高版本。只需将其放入一个新文件中即可。

internal static class ContextUtil
{
    public static HttpControllerContext CreateControllerContext(HttpConfiguration configuration = null, IHttpController instance = null, IHttpRouteData routeData = null, HttpRequestMessage request = null)
    {
        HttpConfiguration config = configuration ?? new HttpConfiguration();
        IHttpRouteData route = routeData ?? new HttpRouteData(new HttpRoute());
        HttpRequestMessage req = request ?? new HttpRequestMessage();
        req.SetConfiguration(config);
        req.SetRouteData(route);

        HttpControllerContext context = new HttpControllerContext(config, route, req);
        if (instance != null)
        {
            context.Controller = instance;
        }
        context.ControllerDescriptor = CreateControllerDescriptor(config);

        return context;
    }

    public static HttpActionContext CreateActionContext(HttpControllerContext controllerContext = null, HttpActionDescriptor actionDescriptor = null)
    {
        HttpControllerContext context = controllerContext ?? ContextUtil.CreateControllerContext();
        HttpActionDescriptor descriptor = actionDescriptor ?? CreateActionDescriptor();
        descriptor.ControllerDescriptor = context.ControllerDescriptor;
        return new HttpActionContext(context, descriptor);
    }

    public static HttpActionContext GetHttpActionContext(HttpRequestMessage request)
    {
        HttpActionContext actionContext = CreateActionContext();
        actionContext.ControllerContext.Request = request;
        return actionContext;
    }

    public static HttpActionExecutedContext GetActionExecutedContext(HttpRequestMessage request, HttpResponseMessage response)
    {
        HttpActionContext actionContext = CreateActionContext();
        actionContext.ControllerContext.Request = request;
        HttpActionExecutedContext actionExecutedContext = new HttpActionExecutedContext(actionContext, null) { Response = response };
        return actionExecutedContext;
    }

    public static HttpControllerDescriptor CreateControllerDescriptor(HttpConfiguration config = null)
    {
        if (config == null)
        {
            config = new HttpConfiguration();
        }
        return new HttpControllerDescriptor() { Configuration = config, ControllerName = "FooController" };
    }

    public static HttpActionDescriptor CreateActionDescriptor()
    {
        var mock = new Mock<HttpActionDescriptor>() { CallBase = true };
        mock.SetupGet(d => d.ActionName).Returns("Bar");
        return mock.Object;
    }
}
于 2018-01-18T02:36:25.663 回答