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嗨，我不想从 xml 加载图片，而是通过 prettyphoto 加载它，这是我的 xml 文件：

<?xml version="1.0" encoding="utf-8"?>
<images>

<image source="Zdjecia/Galeria/Kategoria1/Miniaturki/image1.jpg"                

lightbox="Zdjecia/Galeria/Kategoria1/Duze/image1.jpg"/>


<image source="Zdjecia/Galeria/Kategoria1/Miniaturki/image2.jpg"                

lightbox="Zdjecia/Galeria/Kategoria1/Duze/image2.jpg"/>

    <image source="Zdjecia/Galeria/Kategoria1/Miniaturki/image3.jpg"        

lightbox="Zdjecia/Galeria/Kategoria1/Duze/image3.jpg"/>

    <image source="Zdjecia/Galeria/Kategoria1/Miniaturki/image4.jpg"        

lightbox="Zdjecia/Galeria/Kategoria1/Duze/image4.jpg"/>

    <image source="Zdjecia/Galeria/Kategoria1/Miniaturki/image5.jpg"        

lightbox="Zdjecia/Galeria/Kategoria1/Duze/image5.jpg"/>

    <image source="Zdjecia/Galeria/Kategoria1/Miniaturki/image6.jpg"        

lightbox="Zdjecia/Galeria/Kategoria1/Duze/image6.jpg"/>

    <image source="Zdjecia/Galeria/Kategoria1/Miniaturki/image7.jpg"        

lightbox="Zdjecia/Galeria/Kategoria1/Duze/image7.jpg"/>

    <image source="Zdjecia/Galeria/Kategoria1/Miniaturki/image8.jpg"        

lightbox="Zdjecia/Galeria/Kategoria1/Duze/image8.jpg"/>

    <image source="Zdjecia/Galeria/Kategoria1/Miniaturki/image9.jpg"        

lightbox="Zdjecia/Galeria/Kategoria1/Duze/image9.jpg"/>

    <image source="Zdjecia/Galeria/Kategoria1/Miniaturki/image10.jpg"       

lightbox="Zdjecia/Galeria/Kategoria1/Duze/image10.jpg"/>
</images>

这是我的js函数：

jQuery(window).ready(function($) {
        $.get("XML/Kategoria1.xml",{},function(xml){
            $('image',xml).each(function(i) {
                lightbox = $(this).find("lightbox").text();
            });
        });



        $.fn.prettyPhoto();
        });


        function openLightbox(path) {

            $.prettyPhoto.open(lightbox);

            }

我要打开的第一个图像是“路径”，它是从 Flash 发送的，下一个我想从名为“lightbox”的 xml 加载的图像，但是这个脚本不起作用，任何人都可以告诉我为什么或解释我该怎么做？请寻求帮助。

这是我的 html 文件：

<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd">
<html xmlns="http://www.w3.org/1999/xhtml" lang="pl" xml:lang="pl">
    <head>
        <title>portfolio</title>
        <meta http-equiv="Content-Type" content="text/html; charset=utf-8" />



<link rel="stylesheet" type="text/css" href="css/prettyPhoto.css" media="all"/>
     <script type="text/javascript" src="scripts/jquery-1.4.4.min.js"></script>
        <script type="text/javascript" src="scripts/jquery.prettyPhoto.js"></script>  
     <script type="text/javascript" src="scripts/swfobject.js"></script>
        <script type="text/javascript" src="scripts/swffit.js"></script>
        <script type="text/javascript">
            swfobject.embedSWF("portfolio.swf", "my_flash", "980", "640", "9.0.0", "", false, {wmode:'transparent'});
            swffit.fit("my_flash"); 

$(document).ready(function($) {
    $.get("xml/kategoria1.xml",{},function(xml){
    $('image',xml).each(function(i) {
        lightbox = $(this).find("lightbox").text();
        openLightbox(lightbox);
    });
});

function openLightbox(path) {
    $.prettyPhoto.open(path);
}
        </script>







        <style type="text/css" media="screen">
        html, body { height:100%; background-color: #000000;}
        body { margin:0; padding:0; overflow:hidden; }
        #flashContent { width:100%; height:100%; }
        </style>
    </head>
    <body>
        <div id="my_flash">
            <object classid="clsid:d27cdb6e-ae6d-11cf-96b8-444553540000" width="100%" height="100%" id="portfolio" align="middle">
                <param name="movie" value="portfolio.swf" />
                <param name="quality" value="best" />
                <param name="bgcolor" value="#000000" />
                <param name="play" value="true" />
                <param name="loop" value="true" />
                <param name="wmode" value="transparent" />
                <param name="scale" value="showall" />
                <param name="menu" value="true" />
                <param name="devicefont" value="false" />
                <param name="salign" value="lt" />
                <param name="allowScriptAccess" value="sameDomain" />
                <param name="allowFullScreen" value="true" />
                <!--[if !IE]>-->
                <object type="application/x-shockwave-flash" data="portfolio.swf" width="100%" height="100%">
                    <param name="movie" value="portfolio.swf" />
                    <param name="quality" value="best" />
                    <param name="bgcolor" value="#000000" />
                    <param name="play" value="true" />
                    <param name="loop" value="true" />
                    <param name="wmode" value="transparent" />
                    <param name="scale" value="showall" />
                    <param name="menu" value="true" />
                    <param name="devicefont" value="false" />
                    <param name="salign" value="lt" />
                    <param name="allowScriptAccess" value="sameDomain" />
                    <param name="allowFullScreen" value="true" />
                <!--<![endif]-->
                    <a href="http://www.adobe.com/go/getflash">
                        <img src="http://www.adobe.com/images/shared/download_buttons/get_flash_player.gif" alt="Pobierz odtwarzacz Adobe Flash Player" />
                    </a>
                <!--[if !IE]>-->
                </object>
                <!--<![endif]-->
            </object>
        </div>
    </body>
</html>

我尝试做一些事情，这个脚本从 xml 加载单个图像，任何想法如何从 xml 加载所有“灯箱”图像？

jQuery(window).ready(function($) {
    $.fn.prettyPhoto();
    $.get("xml/kategoria1.xml",{},function(xml){
    $('image',xml).each(function(i) {
        lightbox = $(this).find("lightbox").text();
      openLightbox(lightbox)
    });
});
});

function openLightbox(path) {
    $.prettyPhoto.open(path);
4

1 回答 1

0

用这个交换上面的代码......

$(document).ready(function($) {
    $.get("XML/Kategoria1.xml",{},function(xml){
    $('image',xml).each(function(i) {
        lightbox = $(this).find("lightbox").text();
        openLightbox(lightbox);
    });
});

function openLightbox(path) {
    $.prettyPhoto.open(path);
}
于 2012-08-07T10:30:54.910 回答