unix - 根据匹配模式组合 Unix 文件中的多行

Question

我有一个文件如下：

Country:  USA
Currency: Dollars
Country:  Canada
Currency: Canadian
          Dollars
Country:  Australia
Currency: Australian
          Dollars
Country:  France
Currency: Euro

我必须合并这两行并获得如下输出：

Country:  USA
Currency: Dollars
Country:  Canada
Currency: Canadian Dollars
Country:  Australia
Currency: Australian Dollars
Country:  France
Currency: Euro

我尝试使用tr空格替换换行符，但是没有用。有人可以帮忙吗。

谢谢。

Answer 1

sed ':r;$!{N;br};s/\n[[:space:]]*\([[:alpha:]]\+\n\)/ \1/g' filename

例子：

$ echo 'Country:  USA
> Currency: Dollars
> Country:  Canada
> Currency: Canadian
>           Dollars
> Country:  Australia
> Currency: Australian
>           Dollars
> Country:  France
> Currency: Euro' | sed ':r;$!{N;br};s/\n[[:space:]]*\([[:alpha:]]\+\n\)/ \1/g'
Country:  USA
Currency: Dollars
Country:  Canada
Currency: Canadian Dollars
Country:  Australia
Currency: Australian Dollars
Country:  France
Currency: Euro

说明：r;$!{N;br};将所有文件读入模式空间，然后搜索所有看起来像一些空格后跟一些字母的行，并删除前面的换行符和多余的空格。有关更多信息，请参阅此sed参考。