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我正在关注在线教程，我有 2 种方法可以向 Google Places API 提交查询。不幸的是，我正试图得到回复，它不起作用。我在代码中有一些调试编号。但是，这里是代码。

-(void) queryGooglePlaces{
    NSString *url = @"https://maps.googleapis.com/maps/api/place/search/json?location=-33.8670522,151.1957362&radius=500&types=food&name=harbour&sensor=false&key=myKey";

    //Formulate the string as a URL object.
    NSURL *googleRequestURL=[NSURL URLWithString:url];
    NSLog(@"1.5");
    // Retrieve the results of the URL.
    dispatch_async(kBgQueue, ^{
        NSData* data = [NSData dataWithContentsOfURL: googleRequestURL];
        [self performSelectorOnMainThread:@selector(fetchedData:) withObject:data waitUntilDone:YES];
    });
    NSLog(@"2");
}

-(void)fetchedData:(NSData *)responseData {
    //parse out the json data
    NSError* error;
    NSDictionary* json = [NSJSONSerialization 
                          JSONObjectWithData:responseData 

                          options:kNilOptions 
                          error:&error];

    //The results from Google will be an array obtained from the NSDictionary object with the key "results".
    NSArray* places = [json objectForKey:@"results"]; 

    //Write out the data to the console.
    NSLog(@"Google Data: %@", places);
    NSLog(@"3");
}

在日志中，输出如下：

2012-08-03 16:40:12.411 sCode[25090:1a303] 1.5
2012-08-03 16:40:12.411 sCode[25090:1a303] 2
2012-08-03 16:40:12.512 sCode[25090:1a303] 4
2012-08-03 16:40:12.751 sCode[25090:1a303] Google Data: (
)
2012-08-03 16:40:12.751 sCode[25090:1a303] 3
2012-08-03 16:40:13.628 sCode[25090:1a303] 1
2012-08-03 16:40:14.129 sCode[25090:1a303] 4

谁能告诉我出了什么问题，所以我没有得到回应。？是的，我确实调用[self queryGooglePlaces];了我的ViewDidLoad方法感谢帮助！对不起，如果我太冗长了..只是一个尝试学习的初学者！

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1 回答 1

2

鉴于提供的代码，我最好的猜测是您需要通过添加百分比转义来编码您的 URL 字符串。尝试url像这样创建...

NSString *url = @"https://maps.googleapis.com/maps/api/place/search/json?location=-33.8670522,151.1957362&radius=500&types=food&name=harbour&sensor=false&key=myKey";
url = [url stringByAddingPercentEscapesUsingEncoding:NSUTF8StringEncoding];

You would typically make that into one line, but have shown it as two lines for clarity. This will convert those = and & into properly escaped characters to provide a valid URL.

于 2012-08-06T18:37:29.577 回答