mysql - 如何在mysql中获取两个日期之间的日期？

Question

在 MySql 数据库中有AM_TIMETABLE表

UserId        DateTime
 101        2012-08-08 04:00:00 
 102        2012-08-15 10:00:00
 103        2012-08-18 09:00:00
 104        2012-08-24 05:00:00

我的问题是，我正在传递开始日期和结束日期，然后我将获得DateTime前列日期：

select * from AM_TIMETABLE where DateTime<='2012-08-08 00:00:00' and DateTime>='2012-08-20 00:00:00'

然后我将获得 101,102,103 UserId 的值。但我收到错误please help

Answer 1

BETWEEN为此要好得多。而且你也必须逃避DateTime，因为它是一个保留词。

SELECT * 
FROM   AM_TIMETABLE 
WHERE  `DateTime` BETWEEN '2012-08-08 00:00:00' AND '2012-08-20 00:00:00'

Answer 2

这可能会更好：

select * from AM_TIMETABLE where `DateTime`<='2012-08-20 00:00:00' and `DateTime`>='2012-08-08 00:00:00'

DateTime也可能是保留字，对此不太确定。如果是这种情况，您需要在它们周围加上反引号（前后一个 `）

Answer 3

You need to quote the datetime values.

Answer 4

你必须把日期放在引号里

   set @start_date='2012-08-08 00:00:00';
   set @end_date='2012-08-20 00:00:00';
   select * from AM_TIMETABLE where DateTime<=@start_date and DateTime>=@end_date

Answer 5

日期时间字段必须在引号内：

SELECT * 
FROM AM_TIMETABLE 
WHERE `DateTime` <= '2012-08-08 00:00:00' AND 
      `DateTime` >= '2012-08-20 00:00:00';

或者您可以尝试：

SELECT * 
FROM AM_TIMETABLE 
WHERE `DateTime` NOT BETWEEN '2012-08-08 00:00:00' AND '2012-08-20 00:00:00';

Answer 6

SELECT * FROM AS_TIMETABLE WHERE DateTime BETWEEN CAST('2012-08-08 00:00:00' AS DATETIME) AND CAST('2012-08-08 00:00:00' AS DATETIME);