5

我有一个 MySQL 数据库,它在列中保存一个类列表,每个类都有一个“级别”,它是行的值,每个人都会改变。因此,例如,数学有 0、1、2 和 3 作为可能的值,0 不被选为类,1、2 和 3 分别代表高、中和低。

我有一个 MySQL 查询,它只从用户的数据库行中提取类。

$result = mysql_query("SELECT math, physics, biology, chemistry, english, spanish, history, economics, art, theoryofknowledge, extendedessay FROM users WHERE username = '". $login_session ."'") or die(mysql_error());  

        while($row = mysql_fetch_array( $result )) {
            echo "Math:". $row['math'] ."<br />";
            echo "Physics:". $row['physics'] ."<br />";
            echo "Biology:". $row['biology'] ."<br />";
            echo "Chemistry:". $row['chemistry'] ."<br />";
            echo "English:". $row['english'] ."<br />";
            echo "Spanish:". $row['spanish'] ."<br />";
            echo "History:". $row['history'] ."<br />";
            echo "Economics:". $row['economics'] ."<br />";
            echo "Art:". $row['art'] ."<br />";
            echo "Theory of Knowledge:". $row['theoryofknowledge'] ."<br />";
            echo "Extended Essay:". $row['extendedessay'];
        }

这是用户的输出:

Math:1
Physics:1
Biology:0
Chemistry:2
English:2
Spanish:3
History:0
Economics:1
Art:0
Theory of Knowledge:1
Extended Essay:1

我如何确定用户的级别,而无需在每次调用类时都执行 if 语句?我需要在网站上的多个位置调用课程,并且我想要一种简单的方法来检查用户拥有哪些课程和级别。

谢谢!

4

2 回答 2

12

我认为最好的方法是构建一个 PHP 类,将用户加载到其中并在其中有一个可以接受类(生物学、数学等)并返回用户级别的函数。如果您愿意,您可以编写一些简单的东西来执行所需级别的检查并根据用户是否足够高来返回真或假。

我什至将一些您可能想要扩展的超级基本结构拼凑在一起:

<?php

    class myUser
    // You are making an object here that stores information about your user.
    // This will mean you only need to query that data once from the DB, then
    // you can use it anywhere on the page without needing to do more queries.
    {
        public $math;
        public $biology;
        // I am making public variables here based on your columns
        // You cuold just as easily make an array for example to store them in.

        public function __construct($userID)
        // Making a construct class - meaning you will be able to write a snippet
        // like this: $currentUser = new myUser(6);
        // and the user information will be loaded nicely for you
        {
            $query="select math, biology from users where ID=$userID";
            // database stuff ....
            // this is where you would write your actual code to get the info
            // from the database and populate it properly, not like I did
            // below for this example
            $this->math=4;
            $this->biology=2;
        }

        public function checkUserLevel($myTopic, $reqLevel)
        // Making use of a few things here that I should ntoe:
        // This is a function you can call from the main code below
        // like this: $currentUser->checkUserLevel('math',3)
        // it will return either true or false.
        // I have used variable variables here for the $myTopic to
        // make it easier. You normally access an element differently
        // normally it is like: echo $this->math;  // output 4
        // Also I am using a ternary operator to return the data,
        // which is just a shortcut.
        {
            return ($this->$myTopic>=$reqLevel)? true : false;
        }

        public function returnUserLevel($myTopic)
        {
            return $this->$myTopic;
        }

    }

    $currentUser = new myUser(6);
    // This is creating a new user object based on the class we made above.
    // Further Explanation:
    // We have a class called myUser, but a class is just a schematic.
    // The $currenUser bit defines a new variable in our code.
    // the "= new myUser" bit says that we want to use the schematic above for this variable
    // the "myUser(6)" basically gives the constructor function an ID to get from
    // the database for the user. Because we defined a constructor class that expects
    // an ID, we need to supply it one, else we will get an error.
    // So $currentUser = new myUser(6)
    // really means "Make me a new variable called $currentUser and make it of the myUser
    // class type, and when making it, fetch me the details of student ID 6 and populate it
    // with their data.

    if($currentUser->checkUserLevel('math',3))
    // Now I am using one of the functions called checkUserLevel, supplying it
    // with the two arguments it needs and depending on it it returns true or false
    // doing one action or another.
    {
        echo "The user is at least level 3.\n";
    }
    else
    {
        echo "The user is lower than level 3.\n";
    }

    if($currentUser->checkUserLevel('biology',12))
    // same check, differnt inputs
    {
        echo "The user is at least level 3.\n";
    }
    else
    {
        echo "The user is lower than level 3.\n";
    }


    // You can output like this for example:
    echo "The users math is at: ".$currentUser->math;

    // and I added a little function that will simply return the level for you of the subject you enter.
    echo "The user is at math level ".$currentUser->returnUserLevel('math');

    // lastly you can do something like this:
    $allSubjects=array('math','physics','biology');
    for($i=0;$i<count($allSubjects);$i++)
    {
        echo "The users ".$allSubjects[$i]." level is at ".$currentUser->returnUserLevel($allSubjects[$i])."<br><br>";
    }

?>

代码的输出是:

The user is at least level 3.

The user is lower than level 3.
于 2012-08-06T02:51:04.100 回答
0

一种方法是在用户登录时将所有类的值存储在 PHP 会话变量中:

<?php
    session_start();
    $_SESSION["classes"] = array();       

    $row = mysql_fetch_array($result);
    foreach($row as $class => $level)
    {
        $_SESSION["classes"][$class] = $level;
    }
?>

然后,您可以在站点的任何页面上访问用户的班级级别,直到他们关闭会话或注销:

<?php
    session_start();
    $mathLevel = $_SESSION["classes"]["math"];
?>
于 2012-08-06T02:53:04.943 回答