0

我需要在我的应用程序中显示一个对话框。在此对话框中有一个 Spinner。所以我使用这段代码来显示对话框并填充 Spinner：

public class setup4 extends Activity {

public List<String> materie = new ArrayList<String>();

/** Called when the activity is first created. */
@Override
public void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.setup4);

    Database d = new Database(this);
    SQLiteDatabase db = d.getWritableDatabase();
    Cursor cursor = db.rawQuery("select * from materie", null);
    if (cursor.moveToFirst()) {
        do materie.add(cursor.getString(1)); while (cursor.moveToNext());
    }
    db.close();
}



//On bottone setup 4
public void onSetup4bottone(View v)
{
    AlertDialog.Builder customDialog = new AlertDialog.Builder(this);
    customDialog.setTitle("Aggiungi ora scolastica");
    LayoutInflater layoutInflater = (LayoutInflater)getApplicationContext().getSystemService(Context.LAYOUT_INFLATER_SERVICE);
    View view=layoutInflater.inflate(R.layout.aggiungi_ora,null);
    customDialog.setView(view);

    Spinner spinner = (Spinner) view.findViewById(R.id.aggiungi_ora_materia);
    ArrayAdapter<String> adapter = new ArrayAdapter<String>(view.getContext(),android.R.layout.simple_spinner_item, materie);
    adapter.setDropDownViewResource(android.R.layout.simple_spinner_item);
    spinner.setAdapter(adapter);
    spinner.setOnItemSelectedListener(new OnItemSelectedListener() {
        public void onItemSelected(AdapterView<?> parentView, View selectedItemView, int position, long id) {
            String selected = (String) parentView.getItemAtPosition(position);
            Toast.makeText(
                    getApplicationContext(), 
                    "hai selezionato "+selected, 
                    Toast.LENGTH_LONG
                ).show();
        }

        public void onNothingSelected(AdapterView<?> parentView) {
            // your code here
        }

    });

    customDialog.show();
}
}

微调器正确加载项目，但是当我单击它以更改值时，应用程序崩溃并出现此错误：android.view.WindowManager$BadTokenException: Unable to add window 我也找到了这个线程Android Spinner Error : android.view.WindowManager$BadTokenException ：无法添加窗口，但我无法理解解决方案

解决 了 LayoutInflater layoutInflater = (LayoutInflater)getApplicationContext().getSystemService(Context.LAYOUT_INFLATER_SERVICE);

利用

LayoutInflater layoutInflater = getLayoutInflater();

4

2 回答 2

1

尝试在不同的上下文中添加您的窗口。

更换你的线路ArrayAdapter<String> adapter = new ArrayAdapter<String>(view.getContext(),android.R.layout.simple_spinner_item, materie);

与以下一个：

ArrayAdapter<String> adapter = new ArrayAdapter<String>(setup4.this /**Your activity_name.this*/,android.R.layout.simple_spinner_item, materie);

让我知道它是否有效...

于 2012-08-05T22:57:46.657 回答
0

在你的spinner.setOnItemSelectedListener()，不要打电话getApplicationContext()，而是写这个：

spinner.setOnItemSelectedListener(new OnItemSelectedListener() {
    public void onItemSelected(AdapterView<?> parentView, View selectedItemView, int position, long id) {
        String selected = (String) parentView.getItemAtPosition(position);
        Toast.makeText(
                setup4.this,     //<===THIS LINE IS CHANGED BY ME
                "hai selezionato "+selected, 
                Toast.LENGTH_LONG
            ).show();
    }
于 2012-08-05T21:58:39.827 回答