0

我正在处理一些代码,并陷入了这个存储过程问题......现在花了太长时间看它,所以请如果有人能告诉我我在哪里是一个菜鸟。

我收到以下错误:

错误代码:1064 您的 SQL 语法有错误;检查与您的 MySQL 服务器版本相对应的手册,以获取在 '@ownerid varchar(50); 附近使用的正确语法;声明@active tinyint;声明@subuser tinyint;设置 ' 在第 4 行

在这段代码上:

    DELIMITER //

USE `test`//

DROP PROCEDURE IF EXISTS `getAccount`//

CREATE DEFINER=`peter`@`%` PROCEDURE `getAccount`( IN cid VARCHAR(20))
BEGIN
    DECLARE cardid VARCHAR(50);
    DECLARE @ownerid VARCHAR(50);
    DECLARE @active TINYINT;
    DECLARE @subuser TINYINT;
    SET cardid = MD5( cid + SHA1(cid + 'a salt value'));

    SELECT @active = active, @ownerid = ownerid, @subuser = subuser FROM cards_tbl WHERE cardhash = cardid;

    IF @active = 1 THEN
        IF @subuser = 1 THEN
            SELECT subuser_m2s_tbl.name,subuser_m2s_tbl.image, user_saldo.saldo AS credits FROM subuser_m2s_tbl 
            JOIN user_saldo ON subuser_m2s_tbl.subhash = user_saldo.userhash 
            WHERE subuser_m2s_tbl.subhash = @ownerid;
        ELSE
            SELECT user_m2s_tbl.name,user_m2s_tbl.image, user_saldo.saldo AS credits FROM user_m2s_tbl 
            JOIN user_saldo ON user_m2s_tbl.userhash = user_saldo.userhash 
            WHERE user_m2s_tbl.userhash = @ownerid; 
        END IF;
    END IF; 
    END$$

DELIMITER ;

我是存储过程的新手,所以它非常简单......提前谢谢

4

2 回答 2

1

当您想在 SELECT 语句中将值传递给变量时,您应该使用 ':=' 而不是 '=',否则 MySQL 只会与操作数进行比较。

SELECT
  active_var := active, ownerid_var := ownerid, subuser_var := subuser
FROM
  cards_tbl
WHERE
  cardhash = cardid;

您也可以使用 SELECT INTO 语句,例如 -

SELECT
  active, ownerid, subuser
INTO
  active_var, ownerid_var, subuser_var
FROM
  cards_tbl
WHERE
  cardhash = cardid;

选择语法

于 2012-08-06T06:29:23.203 回答
0

是不是缺少了@

DECLARE cardid VARCHAR(50);

...

DECLARE @cardid VARCHAR(50);
于 2012-08-05T12:38:06.547 回答