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我想读\写一个具有以下结构的二进制文件:

在此处输入图像描述

该文件由“记录”组成。每个“记录”具有以下结构:我将以第一条记录为例

  • (红色)起始字节:0x5A(始终为 1 字节,固定值 0x5A)
  • (绿色)LENGTH 字节:0x00 0x16(总是 2 字节,值可以从“0x00 0x02”变为“0xFF 0xFF”)
  • (蓝色) CONTENT:由 LENGTH 字段的十进制值减去 2 表示的字节数。

在这种情况下,LENGHT 字段值为 22(0x00 0x16 转换为十进制),因此 CONTENT 将包含 20 (22 - 2) 个字节。我的目标是逐条读取每条记录,并将其写入输出文件。实际上我有一个读函数和写函数(一些伪代码):

private void Read(BinaryReader binaryReader, BinaryWriter binaryWriter)
{
    byte START = 0x5A;
    int decimalLenght = 0;
    byte[] content = null;
    byte[] length = new byte[2];

    while (binaryReader.PeekChar() != -1)
    {
        //Check the first byte which should be equals to 0x5A
        if (binaryReader.ReadByte() != START)
        {
            throw new Exception("0x5A Expected");
        }

        //Extract the length field value
        length = binaryReader.ReadBytes(2);

        //Convert the length field to decimal
        int decimalLenght = GetLength(length);

        //Extract the content field value
        content = binaryReader.ReadBytes(decimalLenght - 2);

        //DO WORK
        //modifying the content

        //Writing the record
        Write(binaryWriter, content, length, START);
    }
}

private void Write(BinaryWriter binaryWriter, byte[] content, byte[] length, byte START)
{
    binaryWriter.Write(START);
    binaryWriter.Write(length);
    binaryWriter.Write(content);   
}

如您所见,我已经为 C# 编写了它,但我真的不知道如何使用 C++ 编写它。有人可以指出我正确的方向吗?

4

4 回答 4

3

您需要使用并以二进制模式( )std::ifstream打开文件。std::ios_base::binary

peek非常相似,但如果无法提取字符则返回eof而不是返回。-1并且read将使您能够将给定数量的字节读入一个值。请注意,您熟悉的某些类型 ( byte, type[]) 在 C++ 中不存在或工作方式不同。您可以使用std::vector后者,但您需要byte自己定义。

于 2012-08-05T12:12:36.557 回答
2

我想我会按这个顺序做点什么:

struct record { 
    static const int start = '\x5a';
    std::vector<char> data; // you might prefer unsigned char.
};

std::istream &operator>>(std::istream &is, record &r) { 
    char ch;
    short len;

    is.get(ch);
    verify(ch == record::start);
    is.read((char *)&len, sizeof(len));
    r.data.resize(len);
    is.read(&r.data[0], len);
    return is;
}

std::ostream &operator<<(std::ostream &os, record const &r) { 
    os << record::start;
    short len = (short)r.data.size();
    os.write((char *)&len, sizeof(len));
    os.write(&r.data[0], len);
    return os;
}

要处理一个记录文件,就像你在你的Read(读取、处理和写入数据的东西的名字不好,顺便说一句)中显示的那样,让我们​​首先定义一个函子来处理文件中的单个记录:

class process_record { 
    record operator()(record r) { 
        // code to process a single record goes here
        // it will take one record as input, and return the processed record.
    }
}

然后,要处理文件,我们将使用如下代码:

std::transform(std::istream_iterator<record>(infile),
               std::istream_iterator<record>(),
               std::ostream_iterator<record>(outfile, ""),
               process_record());

[注意:为了简洁起见,我在这里使用了 C 风格的强制转换,但在实际代码中我可能会使用static_casts 代替。]

于 2012-08-05T14:37:20.303 回答
0

谢谢你,这是我能够开发的解决方案:

// TestCPP003.cpp : Defines the entry point for the console application.
//

#include "stdafx.h"

#include "boost\program_options.hpp"
namespace po = boost::program_options;

#include "Util.h"

using namespace std;

int main(int argc, char* argv[])
{
    po::options_description desc("Allowed options");

    desc.add_options()
        ("h", "produce help message")
        ("i", po::value<string>(), "input file")
        ("o", po::value<string>(), "output file");

    po::variables_map vm;
    po::store(po::parse_command_line(argc, argv, desc), vm);

    if (vm.count("h"))
    {
        cout << desc << endl;
        return 0;
    }

    po::notify(vm);

    if (vm.count("i"))
    {
        cout << vm["i"].as<string>() << "\n";
    }

    string sInputFile = vm["i"].as<string>();

    if (fileExists(sInputFile.c_str()))
    {
        cout << "file exists: <" <<  sInputFile << ">" << endl;
    }
    else
    {
        cout << "file not exists: <" <<  sInputFile << ">" << endl;
        cout << "RETURN CODE: 8" << endl;
        return 8;
    }

    string sOutputFile = vm["o"].as<string>();

    static const int START_BYTE = '\x5a';
    static const int AFP_RECORD_HEADER_SIZE = 1;
    static const int AFP_RECORD_LENGTH_SIZE = 2;    
    char * afpHeaderBlock = new char[1];
    char * afpLengthBlock;
    unsigned int afpRecordLength = 0;
    char * afpContentBlock;

    ifstream inputStream(sInputFile, ios::in|ios::binary);
    ofstream outputStream(sOutputFile, ios::out|ios::binary);

    if (inputStream.is_open() && outputStream.is_open())
    {
        while (inputStream.read(afpHeaderBlock, AFP_RECORD_HEADER_SIZE)) 
        {           
            //cout << ToHex(string(afpHeaderBlock, AFP_RECORD_HEADER_SIZE), true) << endl;

            if (START_BYTE == afpHeaderBlock[0])
            {
                cout << "0x5A Found!" << endl;
            }
            else
            {
                cout << "0x5A not Found! - AFP Error" << endl;
            }

            outputStream.write(afpHeaderBlock,  AFP_RECORD_HEADER_SIZE);

            afpLengthBlock = new char[AFP_RECORD_LENGTH_SIZE];
            afpRecordLength = 0;

            inputStream.read(afpLengthBlock, AFP_RECORD_LENGTH_SIZE);

            //cout << ToHex(string(afpLengthBlock, AFP_RECORD_LENGTH_SIZE), true) << endl;

            afpRecordLength = (afpRecordLength << 8) + static_cast<const unsigned char&>(afpLengthBlock[0]);
            afpRecordLength = (afpRecordLength << 8) + static_cast<const unsigned char&>(afpLengthBlock[1]);

            //cout << "AFP Record Length: " << afpRecordLength << endl;

            outputStream.write(afpLengthBlock,  AFP_RECORD_LENGTH_SIZE);

            afpContentBlock = new char[afpRecordLength - AFP_RECORD_LENGTH_SIZE];

            inputStream.read (afpContentBlock, afpRecordLength - AFP_RECORD_LENGTH_SIZE);

            outputStream.write(afpContentBlock,  afpRecordLength - AFP_RECORD_LENGTH_SIZE);
        }

        inputStream.close();
        outputStream.flush();
        outputStream.close();
    }

    cout << "RETURN CODE: 0" << endl;
    return 0;
}
于 2012-08-07T07:50:32.177 回答
0

好的,根据您的回答,我做了一些实验:

string sFile = "C:\Test.bin";
static const int START_BYTE = '\x5a';
char tempByte;

ifstream inputFile (sFile, ios::in);
inputFile.open( sFile, ios::binary );

while (!inputFile.eof()) 
{
    inputFile.get(temptByte);

    cout << "Value of Byte " << hex << static_cast<int>(tempByte) << " hexadecimal" << endl;
}

但是,输出始终显示为:ffffffcc,或者如果未转换为 -52。

如果我做对了,我的代码应该一次读取一个字节的文件,并打印出字节十六进制值。我错了吗 ?

于 2012-08-05T20:38:55.200 回答