2

I need to convert NSString like this : "2012-08-01T12:43:35+02:00" to NSDate, but i don't find the good format...

I use this category code to convert NSString to NSDate :

[NSDate dateFromString:@"2012-08-01T12:43:35+02:00" withFormat:@"yyyy-MM-dd'T'HH:mm:ssZZZZ"];

 

+ (NSDate*) dateFromString:(NSString*)dateString withFormat:(NSString*)format 
{
    return [self dateFromString:dateString withFormat:format andLocaleIdentifier:@"fr"];
}

+ (NSDate*) dateFromString:(NSString*)dateString withFormat:(NSString*)format andLocaleIdentifier:(NSString*)localeIdentifier
{
    NSDateFormatter *dateFormatter = [[NSDateFormatter alloc] init];    
    [dateFormatter setDateFormat:format];
    [dateFormatter setTimeZone:[NSTimeZone localTimeZone]];

    NSLocale *locale = [[NSLocale alloc] initWithLocaleIdentifier:localeIdentifier];
    [dateFormatter setLocale:locale];
    [locale release];

    NSDate *returnDate = [dateFormatter dateFromString:dateString];
    [dateFormatter release];

    return returnDate;
}

I tried all the format i can, but no one is correct...

yyyy-MM-dd'T'HH:mm:ss >> 2012-08-04T18:05:14
yyyy-MM-dd'T'HH:mm:ssv >> 2012-08-04T18:05:14France Time
yyyy-MM-dd'T'HH:mm:ssvv >> 2012-08-04T18:05:14GMT+02:00
yyyy-MM-dd'T'HH:mm:ssvvv >> 2012-08-04T18:05:14GMT+02:00
yyyy-MM-dd'T'HH:mm:ssV >> 2012-08-04T18:05:14CEST
yyyy-MM-dd'T'HH:mm:ssVV >> 2012-08-04T18:05:14GMT+02:00
yyyy-MM-dd'T'HH:mm:ssVVV >> 2012-08-04T18:05:14GMT+02:00
yyyy-MM-dd'T'HH:mm:ssVVVV >> 2012-08-04T18:05:14France Time
yyyy-MM-dd'T'HH:mm:ssz >> 2012-08-04T18:05:14GMT+02:00
yyyy-MM-dd'T'HH:mm:sszz >> 2012-08-04T18:05:14GMT+02:00
yyyy-MM-dd'T'HH:mm:sszzz >> 2012-08-04T18:05:14GMT+02:00
yyyy-MM-dd'T'HH:mm:sszzzz >> 2012-08-04T18:05:14Central European Summer Time
yyyy-MM-dd'T'HH:mm:ssZ >> 2012-08-04T18:05:14+0200
yyyy-MM-dd'T'HH:mm:ssZZ >> 2012-08-04T18:05:14+0200
yyyy-MM-dd'T'HH:mm:ssZZZ >> 2012-08-04T18:05:14+0200
yyyy-MM-dd'T'HH:mm:ssZZZZ >> 2012-08-04T18:05:14GMT+02:00

How can i do ?

[Edit] First ugly solution :

  1. Delete the last colon with a regex
  2. Convert the string with this format "yyyy-MM-dd'T'HH:mm:ssZZZ"

There is the regex

    NSString* dateString = @"2012-08-01T12:43:35+02:00";
    NSMutableString* dateWithoutColonString = [dateString mutableCopy];

    NSRegularExpression* lastColonRegex = [NSRegularExpression
                                           regularExpressionWithPattern:@"([\\+\\-][0-9][0-9]):"
                                           options:NSRegularExpressionCaseInsensitive
                                           error:nil];

    [lastColonRegex replaceMatchesInString:dateWithoutColonString
                              options:NSRegularExpressionCaseInsensitive
                                range:NSMakeRange(0, [dateString  length])
                         withTemplate:@"$1"];
4

2 回答 2

1

使用 [格式化程序 setDateFormat:@"yyyy-MM-dd'T'HH:mm:ssZZZZZ"];

于 2014-09-09T07:34:00.573 回答
0

Apple 讨论了解析 Internet 样式的日期，这与您的代码类似，但有一些更改。它始终使用en_US_POSIX语言环境，并且它使用[NSTimeZone timeZoneForSecondsFromGMT:0]而不是您的本地时区进行解析。试试看，看看结果是否更适合你。

于 2012-08-04T16:42:10.977 回答