我有两张桌子:
Discounts(disid primary key)
Cust(custid primary key, disid ref discount(disid))
现在我需要一个查询来获得custid
所有disid
(折扣券),并且客户可能disid
不止一次包含相同的东西。
尝试以下任一解决方案:
SELECT a.custid, COUNT(a.disid) totalCoupon
FROM cust a
INNER JOIN discounts b
ON b.disid = a.disid
GROUP BY a.custid
或者
SELECT a.custid, COUNT(a.disid) totalCoupon
FROM cust a
INNER JOIN discounts b
ON b.disid = a.disid
GROUP BY a.custid
HAVING COUNT(a.disid) > 1 -- customers having the same (but more than 1)
-- CouponID will only be shown here
select custid, count(distinct disid) from cust
group by custid
having count(*) = (select count(*) from discounts)
SELECT COUNT(DISTINCT D.disid) FROM CUST C
INNER JOIN DISCOUNTS D ON D.disid=C.disid GROUP BY D.disid